问题描述
嗨
我写了以下代码但是while循环对w [i，j]没有任何影响
这有什么问题？
请帮帮我
谢谢
我尝试过：
HiI wrote following code but while loop has not any effect on w[i,j]
what's wrong with this?
help me please
thanks
What I have tried:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace xxxxxxx
{
class Program
{
static void Main(string[] args)
{
int[,] x = new int[,] { { 1, 1 }, { 1, -1 }, { -1, 1 } };
int[] t = new int[] { -1, 1, 1 };
double[,] w = new double[,] { { 0.05, 0.1 }, { 0.2, 0.2 }, { 0.5, 0.5 } };
double[] b = new double[] { 0.3, 0.15, 0.5 };
bool ep = true;
int x1;
int x2;
double zin1;
double zin2;
int z1;
int z2;
double yin;
int y;
int pp = 0;
while (pp < 15)
{
//ep = false;
for (int j = 0; j < 3; j = j + 1)
{
x1 = x[j, 0];
x2 = x[j, 1];
zin1 = b[0] + (x1 * w[0, 0]) + (x2 * w[1, 0]);
zin2 = b[1] + (x1 * w[0, 1]) + (x2 * w[1, 1]);
if (zin1 >= 0)
{
z1 = 1;
}
else
{
z1 = -1;
}
if (zin2 >= 0)
{
z2 = 1;
}
else
{
z2 = -1;
}
yin = b[2] + z1 * w[2, 0] + z2 * w[2, 1];
if (yin >= 0)
{
y = 1;
}
else
{
y = -1;
}
if (y != t[j])
{
//ep = true;
if (t[j] == 1)
{
if (Math.Abs(zin1) < Math.Abs(zin2))
{
b[0] = b[0] + 0.5 * (1 - zin1);
w[0, 0] = w[0, 0] + 0.5 * (1 - zin1) * x1;
w[1, 0] = w[1, 0] + 0.5 * (1 - zin1) * x2;
}
else
{
b[1] = b[1] + 0.5 * (1 - zin2);
w[0, 1] = w[0, 1] + 0.5 * (1 - zin2) * x1;
w[1, 1] = w[1, 1] + 0.5 * (1 - zin2) * x2;
}
}
else if(t[j] == -1)
{
if (zin1 > 0 && zin2 > 0)
{
b[0] = b[0] + 0.5 * (-1 - zin1);
w[0, 0] = w[0, 0] + 0.5 * (-1 - zin1) * x1;
w[1, 0] = w[1, 0] + 0.5 * (-1 - zin1) * x2;
b[1] = b[1] + 0.5 * (-1 - zin2);
w[0, 1] = w[0, 1] + 0.5 * (-1 - zin2) * x1;
w[1, 1] = w[1, 1] + 0.5 * (-1 - zin2) * x2;
}
else if (zin1 > 0 && zin2 <= 0)
{
b[0] = b[0] + 0.5 * (-1 - zin1);
w[0, 0] = w[0, 0] + 0.5 * (-1 - zin1) * x1;
w[1, 0] = w[1, 0] + 0.5 * (-1 - zin1) * x2;
}
else if (zin1 < 0 && zin2 > 0)
{
b[1] = b[1] + 0.5 * (-1 - zin2);
w[0, 1] = w[0, 1] + 0.5 * (-1 - zin2) * x1;
w[1, 1] = w[1, 1] + 0.5 * (-1 - zin2) * x2;
}
}
}
}
pp = pp + 1;
}
Console.WriteLine("b1:{0} , b2:{1} , b3:{2} \n w00:{3} , w10:{4} , w01:{5}, w11:{6}", b[0], b[1], b[2], w[0, 0], w[1, 0], w[0, 1], w[1, 1]);
int[,] test = new int[,] { { -1, -1 } };
x1 = test[0, 0];
x2 = test[0, 1];
zin1 = b[0] + (x1 * w[0, 0]) + (x2 * w[1, 0]);
zin2 = b[1] + (x1 * w[0, 1]) + (x2 * w[1, 1]);
if (zin1 >= 0)
z1 = 1;
else
z1 = -1;
if (zin2 >= 0)
z2 = 1;
else
z2 = -1;
yin = b[2] + w[2, 0] * z1 + w[2, 1] * z2;
if (yin >= 0)
y = 1;
else
y = -1;
if (y == 1)
{
Console.WriteLine("1");
}
else
{
Console.WriteLine("-1");
}
Console.ReadLine();
}
//private static void f(double zin, int y)
// {
// if (zin >= 0)
// y = 1;
// else
// y = -1;
// }
}
}推荐答案
Input Expected output Actual output
1 2 1
2 4 4
3 6 9
4 8 16然后很明显问题出在将它加倍的位 - 它不会将自身加到自身上，或者将它乘以2，它会将它自身相乘并返回输入的平方。
所以，你可以查看代码和很明显，它在某处：
Then it's fairly obvious that the problem is with the bit which doubles it - it's not adding itself to itself, or multiplying it by 2, it's multiplying it by itself and returning the square of the input.
So with that, you can look at the code and it's obvious that it's somewhere here:
private int Double(int value)
{
return value * value;
}
一旦你知道可能出现的问题，就开始使用调试器找出原因。在您的行上设置一个断点：
Once you have an idea what might be going wrong, start using the debugger to find out why. Put a breakpoint on your line:
while (pp < 15)
并运行您的应用。在执行代码之前，请考虑代码中的每一行应该做什么，并将其与使用Step over按钮依次执行每一行时实际执行的操作进行比较。它符合您的期望吗？如果是这样，请转到下一行。
如果没有，为什么不呢？它有何不同？
这是一项非常值得开发的技能，因为它可以帮助你在现实世界和发展中。和所有技能一样，它只能通过使用来改善！
and run your app. Think about what each line in the code should do before you execute it, and compare that to what it actually did when you use the "Step over" button to execute each line in turn. Did it do what you expect? If so, move on to the next line.
If not, why not? How does it differ?
This is a skill, and it's one which is well worth developing as it helps you in the real world as well as in development. And like all skills, it only improves by use!
我写了以下代码虽然循环对w [i，j]
没有任何影响但这有什么问题？
I wrote following code but while loop has not any effect on w[i,j]
what's wrong with this?
调试器将显示你的代码正在做什么变量值。
有一个工具可以让你看到代码在做什么，它的名字是调试器。它也是一个很好的学习工具，因为它向你展示了现实，你可以看到哪种期望与现实相符。
当你不明白你的代码在做什么或为什么它做它做的时候，答案就是答案是调试器。
使用调试器查看代码正在执行的操作。只需设置断点并查看代码执行情况，调试器允许您逐行执行第1行并在执行时检查变量。
[]
[]
调试器在这里向您展示您的代码正在做什么，您的任务是与它应该做什么进行比较。
调试器中没有魔法，它不是'找到错误，它只是帮助你。当代码没有达到预期的效果时，你就会接近一个错误。
The debugger will show you what your code is doing and values of variables.
There is a tool that allow you to see what your code is doing, its name is debugger. It is also a great learning tool because it show you reality and you can see which expectation match reality.
When you don't understand what your code is doing or why it does what it does, the answer is debugger.
Use the debugger to see what your code is doing. Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute.
Debugger - Wikipedia, the free encyclopedia[^]
Debugging C# Code in Visual Studio - YouTube[^]
The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't find bugs, it just help you to. When the code don't do what is expected, you are close to a bug.
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