本文介绍了Android中5秒后执行函数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我是 android 开发的新手,现在我的启动器活动只显示 5 秒,之后我想检查用户是否登录或未运行并执行操作.
I am new in android development and now my launcher activity show only 5 seconds and after that I want to check the user is logged in or not function and perform the actions.
这是我的代码.
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
exactPreferences = getSharedPreferences("ExactPreference",MODE_PRIVATE);
setContentView(R.layout.activity_landing_page);
session = exactPreferences.getString(Model.getSingleton().SHARED_SESSION_ID,null);
Log.i("Session Id",session);
displayData(); // I want to perform this function after 5 seconds.
}
private void displayData() {
if(session.equals("")){
Intent loginIntent = new Intent(LandingPage.this,
LoginActivity.class);
startActivity(loginIntent);
Log.i("User Logged In", "False");
}
else
{
Intent objIntent = new Intent(LandingPage.this,
IndexPageActivity.class);
startActivity(objIntent);
Log.i("User Logged In", "True");
}
}
推荐答案
你可以使用Handler来增加一些延迟.调用方法displayData()
如下,这样它会在5后执行秒.
You can use the Handler to add some delay.Call the method displayData()
as below so that it will be executed after 5 seconds.
new Handler().postDelayed(new Runnable() {
@Override
public void run() {
displayData();
}
}, 5000);
注意:不要使用像 Thread.sleep(5000);
这样的线程,因为它会阻塞您的 UI 并使其无响应.
Note : Do not use the threads like Thread.sleep(5000);
because it will block your UI and and makes it irresponsive.
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