问题描述
我的bash脚本运行在后台并等待指令等待它停止一些程序。但是有一个高的可能性，即后台进程就会被杀死，因为它需要太多内存。我希望我的脚本来为最终轻轻一杀一个过程有不同的反应。如何检查这个条件？
My bash script is running some program in background and with wait command waits for it to stop. But there is a high possibility that the background process will be killed because it takes too much memory. I want my script to react differently for a process that ended up gently and for a killed one. How do I check this condition?
推荐答案
请确保您的命令信号的成功（与出口code 0），当它成功，和失败（不为零），当它失败。
Make sure your command signals success (with exit code 0) when it succeeds, and failure (non-zero) when it fails.
当一个进程被OOM杀手用SIGKILL杀死，信号故障是自动的。 （外壳会考虑信号的退出code终止的进程是128 +信号数，所以128 + 9 = 137 SIGKILL）。
When a process is killed with SIGKILL by the OOM killer, signaling failure is automatic. (The shell will consider the exit code of signal terminated processes to be 128 + the signal number, so 128+9=137 for SIGKILL).
您然后使用一个事实，即等待somepid 与同code，因为它在if语句上等待命令退出：
You then use the fact that wait somepid exits with the same code as the command it waits on in an if statement:
yourcommand &
pid=$!
....
if wait $pid
then
echo "It exited successfully"
else
echo "It exited with failure"
fi
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