flask restful:将参数传递给GET请求

问题描述

我想通过以下方式创建支持GET请求的资源:

I want to create a resource that supports GET request in following way:

/bar?key1=val1&key2=val2

我尝试了此代码，但无法正常工作

I tried this code, but it is not working

app = Flask(__name__)
api = Api(app)

class BarAPI(Resource):
    def get(key1, key2):
        return jsonify(dict(data=[key1, key2]))

api.add_resource(BarAPI, '/bar', endpoint='bar')

谢谢！

推荐答案

Flask可以通过请求解析参数

Flask can parse arguments through request

from flask import request

您可以在需要GET参数的块中使用以下行. GET在@app.route()声明中声明.

You can use following lines in the block that requires GET parameters. GET is declared in @app.route() declaration.

args = request.args
print (args) # For debugging
no1 = args['key1']
no2 = args['key2']
return jsonify(dict(data=[no1, no2])) # or whatever is required

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