如何从PHP调用Java脚本函数

问题描述

有人可以帮助我从PHP调用Java脚本函数吗?

Can any one help me in calling java script function from PHP

<script>
function HideDiv(id)
{
  document.getElementById(id).style.display="block";
}

</script>

if($Acidity=="Acidity")
{
        echo"Raj";
	echo "<SCRIPT LANGUAGE='javascript'>HideDive('Acidity');</SCRIPT>";

}

我需要使Div可见.

谢谢！

I need to make the Div Visible.

Thanks!

推荐答案

我需要使Div可见.

谢谢！

I need to make the Div Visible.

Thanks!

<script type="text/javascript">
function HideDiv(id)
{
    document.getElementById(id).style.display="block";
}
</script>

if(

我在您的代码中发现了两个问题:
1.用于选择脚本语言的脚本标签的属性称为type
并以文本/javascript"作为JavaScript代码.
2.您编写的函数名为HideDiv(id)，您称为函数HideDive(id).


希望您能将其与这些更正一起使用！


最好的问候，


曼弗雷德

PS:如果该函数的语义是显示div而不是隐藏div，则应将其称为ShowDiv.

There are two issues I found in your code:
1. Script tag''s attribute to select scripting lanuage is called type
and takes "text/javascript" for javascript code.
2. Function you wrote is named HideDiv(id) you called a function called HideDive(id).


I hope you get it to work with these corrections!


Best Regards,


Manfred

PS: The function should be called ShowDiv if its semantic is to reveal the div and not to hide it.

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