问题描述
结构是:
struct
{
int x;
struct
{
int y, z;
} nested;
}
i={.nested.y = 5, 6, .x = 1, 2};
问题:结果是 i.nested.y = 2;i.nested.z = 6;
Question: The result is i.nested.y = 2; i.nested.z = 6;
我无法理解或理解这一点,内部也是一个结构体但联合体,所以有人可以帮助我吗?
I cannot get or understand this, the inner one is also a struct but union, so could anyone help me?
推荐答案
好吧,首先让我说这是一种很糟糕的初始化结构的方式,如果这是一个家庭作业问题 - 这也不是一个很好的问题.
然而,考虑到手头的问题,我认为初始化过程中发生的事情是这样的:首先,y 被初始化为 5,作为结构中的下一个成员的 z 被初始化为 6.然后,x 被初始化为 1结构中的下一个成员,在本例中为 y,被初始化为 2(覆盖 5).
Ok, first of all let me say that this is a terrible way to initialize a struct, and if it's a homework question - it's not a very good one either.
However, given the problem at hand, what I believe is happening in the initialization is this: first, y is initialized to 5, and z, being the next member in the struct, is initialized to 6. Then, x is initialized to 1 and the next member in the struct, in this case y, is initialized to 2 (which overwrites the 5).
还有一点需要注意,嵌套结构不是联合,而是结构——首先,因为这是代码所说的,而且因为如果它是联合——这将是不可能的这种情况下 y 和 z 具有不同的值,因为它们都将保存在内存中的同一位置.
Something important to note as well, is that the nested struct isn't a union, but a struct - first of all, because that's what the code says, but also because if it were a union - it would be impossible in this case for y and z to have different values, since both would be kept in the same location in the memory.
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