本文介绍了在深层链接URL iOS中获取参数的值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
每个人.我的问题是:如何从深层链接URL获取数据?我有两个应用程序,我想使用深层链接将数据从app1发送到app2.我在app1上有一个按钮,可以单击并打开app2,然后app 2将通过深链接URL从app1中获取数据.
everyone.My question is: How can I get data from deep link URL?I have two apps and I want to send data from app1 to app2 using the deep link.I have a button on app1 to click and open app2 then app 2 will get data from app1 by deep link URL.
这是我在app1中发送按钮的代码:
Here is my code of button send in app1:
@IBAction func btnSend_Clicked(_ sender: Any) {
let text = self.txtInput.text?.replacingOccurrences(of: " ", with: "%20")
UIApplication.shared.open(URL(string: "myapp://?code=\(text!)")!, options: [:], completionHandler: nil)
}
那么,如何从app2中的Deeplink网址(代码参数)获取数据?
so, How can i get data from deeplink url (code parameter) in app2?
真的谢谢您的帮助!!!!
Really Thanks for your help !!!!
推荐答案
您可以在Appdelegate中实现以下代码:
You implement this code in Appdelegate:
func application(_ app: UIApplication, open url: URL, options: [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {
let urlComponents = URLComponents(url: url, resolvingAgainstBaseURL: false)
let items = (urlComponents?.queryItems)! as [NSURLQueryItem]
if (url.scheme == "myapp") {
var vcTitle = ""
if let _ = items.first, let propertyName = items.first?.name, let propertyValue = items.first?.value {
vcTitle = url.query!//"propertyName"
}
}
return false
}
这篇关于在深层链接URL iOS中获取参数的值的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!