问题描述
我想在测试ASP.NET MVC3应用程序来填充组合框(RAD Telerik的组合框)。
我定义我的ASPX页面上的组合框,并在控制器中我已经定义了动作调用返回一个JsonResult。
我遇到的问题是,我已经使用Web Service的返回结果为JSON字符串。我怎样才能通过直接从web服务的响应。
下面是code的片段:
ASPX页面:
<%Html.Telerik()组合框()
。名称(cbRefTables)
.DataBinding(B =>乙
阿贾克斯()
。选择(GetCALMdata,通用)结果
)
.Render();
%>
控制器:所谓CommomController
公共JsonResult GetCALMdata()
{
CALMwsP.wsCALMSoapClient WSC =新CALMwsP.wsCALMSoapClient(wsCALMSoap);
串结果集= wsC.GetRefTables(P_1,P_2,P_3,P_4); 返回??; - 我想返回已格式化的结果集。
}
如果在的ResultSet
字符串已经是JSON(而不是包裹在任何XML),那么你要返回 ContentResult类型
带正是字符串内容:
公共ContentResult类型GetCALMdata()
{
CALMwsP.wsCALMSoapClient WSC =新CALMwsP.wsCALMSoapClient(wsCALMSoap);
串结果集= wsC.GetRefTables(P_1,P_2,P_3,P_4); 返回的内容(结果集,应用/ JSON);
}
您不想使用 JsonResult
或 JSON()
助手在这种情况下,因为这是怎么回事落得重新序列化的JSON。
I am trying to populate a ComboBox (Telerik RAD COmboBox) in a test ASP.NET MVC3 app.
I have defined the ComboBox on my ASPX page and in the controller I have defined the action call that returns a JsonResult.
The problem I am having is that the Web Service I am using already returns the resultset as a JSON string. How can I pass the response from the Webservice directly.
Here is the snippets of code:ASPX page:<% Html.Telerik().ComboBox() .Name("cbRefTables") .DataBinding(b => b .Ajax() .Select("GetCALMdata","Common")
) .Render(); %>
Controller: called CommomController
public JsonResult GetCALMdata()
{
CALMwsP.wsCALMSoapClient wsC = new CALMwsP.wsCALMSoapClient("wsCALMSoap");
string resultset = wsC.GetRefTables("P_1", "P_2", "P_3", "P_4");
return ??; -- I want to return resultset which is already formatted.
}
If the resultset
string is already JSON (and not wrapped in any XML), then you'd want to return a ContentResult
with exactly that string as the content:
public ContentResult GetCALMdata()
{
CALMwsP.wsCALMSoapClient wsC = new CALMwsP.wsCALMSoapClient("wsCALMSoap");
string resultset = wsC.GetRefTables("P_1", "P_2", "P_3", "P_4");
return Content(resultset, "application/json");
}
You don't want to use JsonResult
or the Json()
helper in this case, because that's going to end up re-serializing your JSON.
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