本文介绍了如何获得大于零值的sqlserver的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在sqlserver中进行了查询。代码如下。



 选择 ReceiptNo,S_Adm_No,paid_date, S_Adm_No,Class,S_Name,S_F_Name,Mode_Payment,ChqNo,ChqDated,bank_Name,For_the_Month,
FHeadId,FHead,Fine,TotalAmount,Concession,payableAmount,SUM(4月+ 5月+ 6月+ 7月+ 8月+ 9月+ 10月+ Nov + [Dec] + Jan + Feb + Mar) as FEE
来自 View_Fee_Receipt_Students 其中 ReceiptNo = ' AIS / 16-17 / 00096' group by ReceiptNo,
S_Adm_No,paid_date,S_Adm_No,Class,S_Name,S_F_Name,Mode_Payment ,ChqNo,ChqDated,bank_Name,For_the_Month,
Fine,TotalAmount,FHeadId,FHead,Concession,payableAmount





我的问题是,如何在费用大于零的情况下获得价值...



我有什么尝试过:



............................ .............................

解决方案



I have made a query in sqlserver. the code is below.

select ReceiptNo, S_Adm_No, paid_date, S_Adm_No, Class, S_Name, S_F_Name, Mode_Payment,ChqNo,ChqDated, bank_Name, For_the_Month ,
FHeadId, FHead,Fine, TotalAmount, Concession, payableAmount, SUM (Apr + May+Jun+Jul+Aug+Sep+Oct+Nov+[Dec]+Jan+Feb+Mar) as FEE
from View_Fee_Receipt_Students where ReceiptNo='AIS/16-17/00096' group by ReceiptNo,
S_Adm_No, paid_date, S_Adm_No, Class, S_Name, S_F_Name, Mode_Payment,ChqNo,ChqDated, bank_Name, For_the_Month ,
Fine, TotalAmount, FHeadId, FHead, Concession, payableAmount



My question is, how to get value where fee has greater than zero...

What I have tried:

.........................................................

解决方案



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08-04 03:07
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