问题描述
我的项目是通过使用被动红外传感器检测运动来实现自动照明.
My project is to allow automatic lightening by detecting motion using PIR Sensors.
这就是我想做的:
当第一个运动传感器inputpin"为高电平时,这意味着检测到运动 1,ledPin1 设置为 HIGH...., 如果是LOW ledpin2 应该是HIGH.
when the first motion sensor "inputpin" is HIGH which means a motion1 is detected , ledPin1 is set to HIGH.... then I check the signal from the other PIR sensor "inputpin2" if it is HIGH ledPin3 should be HIGH , If it is LOW ledpin2 should be HIGH.
我写了这段代码,但它实际做的是在从第一个传感器inputPin"检测到运动后,ledPin3 被设置为高,就好像第二个传感器总是高!
I wrote this code , but what it actually do is after a motion is detected from the first sensor"inputPin" , ledPin3 is set to high as if the second sensor is always HIGH !
谁能帮我解决这个问题.谢谢
Can any one help me with this problem.Thanks
` ``
int ledPin1 = 13; // choose the pin for the LED
int ledPin2 = 12;
int ledPin3 = 11;
int inputPin = 2; // choose the input pin (for PIR sensor)
int inputPin2 = 1;
int pirState1 = LOW; // we start, assuming no motion detected
int pirState2 = LOW;
int val = 0; // variable for reading the pin status
int val2 = 0;
int pinSpeaker = 10; //Set up a speaker on a PWM pin (digital 9, 10, or 11)
void setup() {
pinMode(ledPin1, OUTPUT); // declare LED as output
pinMode(ledPin2, OUTPUT); // declare LED as output
pinMode(ledPin3, OUTPUT);
pinMode(inputPin, INPUT); // declare sensor 1 as input
pinMode(inputPin2, INPUT); // declare sensor 2 as input
// pinMode(pinSpeaker, OUTPUT);
Serial.begin(9600);
}
void loop(){
val = digitalRead(inputPin); // read input value
if (val == HIGH) { // check if the input is HIGH
digitalWrite(ledPin1, HIGH); // turn LED ON
delay (1500);
if (pirState1 == LOW) {
// we have just turned on
Serial.println("Motion1 detected!");
// We only want to print on the output change, not state
pirState1 = HIGH;
}
delay (1500);
// check sensor 2 after delay
val2 = digitalRead(inputPin2);
if (val2 == HIGH){
digitalWrite(ledPin2, LOW);
delay(1500);
digitalWrite(ledPin3,HIGH);
//playTone(300, 160);
delay(1500);
if (pirState2 == LOW) {
// we have just turned on
Serial.println("Motion1 from sensor 2 detected!");
// We only want to print on the output change, not state
pirState2 = HIGH;
}
}
if(val2 == LOW){
digitalWrite(ledPin2, HIGH);
//playTone(300, 160);
delay(1500);
digitalWrite(ledPin3,LOW);
delay(1500);
}
} else {
digitalWrite(ledPin1, LOW); // turn LED OFF
delay (1500);
digitalWrite(ledPin2, LOW); // may be already
//playTone(0, 0);
delay(1500);
digitalWrite(ledPin3, LOW); // turn LED OFF
delay (1500);
if (pirState1 == HIGH){
// we have just turned of
Serial.println("Motion ended!");
// We only want to print on the output change, not state
pirState1 = LOW;
}
if (pirState2 == HIGH){
// we have just turned of
Serial.println("Motion ended!");
// We only want to print on the output change, not state
pirState2 = LOW;
}
}
}
// duration in mSecs, frequency in hertz
void playTone(long duration, int freq) {
duration *= 1000;
int period = (1.0 / freq) * 1000000;
long elapsed_time = 0;
while (elapsed_time < duration) {
digitalWrite(pinSpeaker,HIGH);
delayMicroseconds(period / 2);
digitalWrite(pinSpeaker, LOW);
delayMicroseconds(period / 2);
elapsed_time += (period);
}
}
`
推荐答案
例如将 inputPin2 从 1 更改为 3.只是不要使用引脚 0 或 1(分配给 Tx 和 Rx 的引脚),希望能奏效.
Change inputPin2 from 1 to 3 for example. Just don't use the pins 0 or 1 (those assigned for Tx and Rx), hope this works.
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