本文介绍了Groovy MOP invokeMethod的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我试图理解invokeMethod如何拦截Groovy中的方法调用。我似乎无法得到最基本的例子工作。
您需要调用 invokeMethod 截取后。
类Person实现GroovyInterceptable {
def invokeMethod(String name ,args){
System.out.println调用invokeMethod $ name $ args
metaClass.getMetaMethod(name,args).invoke(this,args)
}
def greet(){
System.out.printlnHello from greet()
}
}
def p = new Person()
p.greet()
是的,您对 println 。必须使用SOP。
I am trying to understand how invokeMethod intercepts method calls in Groovy. I can't seem to get the most basic of examples working though.
class Person implements GroovyInterceptable { def invokeMethod(String name,args) { println "called invokeMethod $name $args" } def greet() { println "Hello from greet()" } } def p = new Person() p.greet()If I try and run this example I get the following error. What am I missing?
Caught: java.lang.StackOverflowError java.lang.StackOverflowError at Person.invokeMethod(Person.groovy:4) at Person.invokeMethod(Person.groovy:4) at Person.invokeMethod(Person.groovy:4) ...解决方案You need to invoke the actual method from invokeMethod after the interception.
class Person implements GroovyInterceptable { def invokeMethod(String name,args) { System.out.println "called invokeMethod $name $args" metaClass.getMetaMethod(name, args).invoke(this, args) } def greet() { System.out.println "Hello from greet()" } } def p = new Person() p.greet()And yes you are correct about println. Have to use SOP.
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