问题描述
我有一个表单，当我单击提交"时，我不希望页面刷新，这就是我添加AJAX来实现此目的的原因，如您所见.问题是它不起作用.
I have a form, when i click on submit i dont want the page to refresh, thats why i added AJAX to achieve this as you can see. The problem is that its not working.
<form id="formFooter" action="" method="post">
<h3>Select your trademark</h3>
<select class="form-control" name="trademark">
<option></option>
<option>©</option>
<option>™</option>
<option>®</option>
</select>
<h3>Your company name</h3>
<input class="form-control" type="text" name="companyName" placeholder="Your company name" />
<h3>Background Color</h3>
<input class="form-control" placeholder="(e.g. 00ff00)" type="text" name="backgroundColor">
<h3>Font Color</h3>
<input class="form-control" placeholder="(e.g. 00ff00)" type="text" name="fontColor">
<h3>Opacity</h3>
<input class="form-control" placeholder="(Pick a value between 0 and 1 e.g. 0.3)" type="text" name="opacity">
<br/>
<br/>
<button class="form-control" id="run" type="submit" name="submit">Generate footer</button>
</form>
<div id="showData"> </div>
<script type="text/javascript">
$('#run').on("click", function (e) {
var formData = new FormData($('#myForm')[0]);
$.ajax({
url: "script.php",
type: 'POST',
data: formData,
success: function (data) {
$('#showData').html(data);
},
cache: false,
contentType: false,
processData: false
});
return false;
});
</script>
这是script.php:
Here is the script.php:
<?php
function footerPreview ()
{
echo "<h3>Preview:</h3>";
date_default_timezone_set('UTC');
$trademark = $_POST["trademark"];
$company = $_POST["companyName"];
$date = date("Y");
//style
$backgroundColor = $_POST['backgroundColor'];
$fontColor = $_POST['fontColor'];
$opacity = $_POST['opacity'];
echo "<div id='generated_footer_date' style='background-color:$backgroundColor; color:$fontColor; opacity: $opacity; ' >$trademark $date $company </div>";
}
// generate result for the head
function rawHead()
{
$head = htmlspecialchars('<head>
<meta charset="utf-8">
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
<link href="https://fonts.googleapis.com/css?family=Raleway:200" rel="stylesheet">
</head>',ENT_QUOTES);
echo "<pre><h4>Put this code inside your head tags</h4>$head</pre>";
}
// generate result for the body
function rawBody ()
{
$body1of5 = htmlspecialchars('<div id="footer_date">',ENT_QUOTES);
$body2of5 = $_POST["trademark"];
$body3of5 = date("Y");
$body4of5 = $_POST["companyName"];
$body5of5 = htmlspecialchars('</div>',ENT_QUOTES);
echo "<pre><h4>Put this code inside your body tags</h4>$body1of5 $body2of5 $body3of5 $body4of5 $body5of5 </pre>";
}
// generate result for the CSS
function rawCSS ()
{
$opacity = $_POST['opacity'];
$backgroundColor = $_POST['backgroundColor'];
$fontColor = $_POST['fontColor'];
echo
"<pre>
<h4>Put this code in your websites stylesheet</h4>
color:$fontColor;
background-color:$backgroundColor;
opacity:$opacity;
width:100%;
text-align:center;
padding-top:15px;
height:50px;
font-family: 'Raleway', sans-serif;
right: 0;
bottom: 0;
left: 0;
position:fixed;
</pre>";
}
// Generate eveything by one click
if(isset($_POST['submit']))
{
footerPreview();
rawHead();
rawBody();
rawCSS();
}
?>
当我单击提交"时，没有任何反应.我希望在不刷新的情况下在同一页面上生成script.php.
When i click on submit nothing happens. I want the script.php to be generate on the same page without refreshing.
推荐答案
您可以将Ajax请求变得非常简单，如下所示:
首先，这里不需要使用FormDate，因为在<form>中没有任何file输入，因此您可以在请求中使用serialize()数据，例如:
First of all no need to use FormDate here, because you don't have any file input in your <form>, so you can use serialize() data in your request as:
var formData = $("#myForm").serialize();
第二，您只是在PHP中打印HTML，这意味着您只需要打印html，因此您可以在此处使用dataType=HTML:
Second, you are just printing the HTML in your PHP, it means you just need to print html, so you can use dataType=HTML here as:
dataType: "html",
第三，还有另一件事将帮助您进行调试，在顶部的script.php文件中添加print_r($_POST)并检查控制台.
Third, one more thing will help you in debugging, add print_r($_POST) in your script.php file at top and check the console.
修改后的请求:
$(document).ready(function(){
$("#run").click(function(){
var formData = $("#myForm").serialize();
$.ajax({
type: "POST",
url: "script.php",
data: formData,
dataType: "html",
success: function(response)
{
$('#showData').html(response);
},
beforeSend: function()
{
//any loader
}
});
return false;
});
});
更新:
看看这个数组，在$_POST的结果中没有submit，因此您有两个选择来更改它:
Look at this array, you don't have submit in the result of $_POST so you have two options to change this:
1)您可以使用count()功能检查if(count($_POST) > 0).
1) You can use count() function for checking if(count($_POST) > 0).
2)或者您可以使用<input type='submit' name='submit'>代替<button type='submit' name='submit'>
2) Or you can use <input type='submit' name='submit'> instead of <button type='submit' name='submit'>
这篇关于AJAX方法不起作用的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！