Javascript-如何在特定的div类内从标签获取属性值?

本文介绍了Javascript-如何在特定的div类内从标签获取属性值?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我需要从以下位置检索值的HTML代码段

Snippet of HTML code I need to retrieve values from:

<div class="elgg-foot">
  <input type="hidden" value="41" name="guid">
  <input class="elgg-button elgg-button-submit" type="submit" value="Save">
</div>

我需要获取值41，该值非常简单:

I need to get the value 41, which is simple enough with:

var x = document.getElementsByTagName("input")[0];
var y = x.attributes[1].value;

但是我需要确保我实际上是在"elgg-foot"内部检索值，因为HTML代码中有多个div类.

However I need to make sure I'm actually retrieving values from inside "elgg-foot", because there are multiple div classes in the HTML code.

我可以得到这样的课程:

I can get the class like this:

var a = document.getElementsByClassName("elgg-foot")[0];

然后我尝试以各种方式将其与 var x 组合在一起，但是我真的不知道这样做的语法/逻辑.例如:

And then I tried to combine it in various ways with var x, but I don't really know the syntax/logic to do it.For example:

var full = a.getElementsByTagName("input")[0];

所以:从唯一类elg-foot内部检索值41.

So: Retrieve value 41 from inside unique class elg-foot.

我花了数小时在此搜索，但找不到解决方案(部分原因是我不确切知道要搜索什么)

I spent hours googling for this, but couldn't find a solution (partly because I don't know exactly what to search for)

谢谢大家的回答，它们似乎都可以奏效.我自己几乎可以正常工作，只是在原始代码中的某个地方忘记了 [0] .同样欣赏JQuery，以前从未使用过它:-)

Thanks for the answers everyone, they all seem to work. I almost had it working myself, just forgot a [0] somewhere in my original code. Appreciate the JQuery as well, never used it before :-)

推荐答案

最简单的方法是使用jQuery并使用CSS选择器:

The easiest way is to use jQuery and use CSS selectors:

$(.elgg-foot")确实总是会为您提供一个"elgg-foot"类的元素，但是如果您更进一步，则可以使用后代选择器:

$(".elgg-foot") will indeed always get you an element with class "elgg-foot", but if you go one step further, you can use descendent selectors:

$(".elgg-foot input[name='guid']").val()

这确保您仅获得名为guid的输入，该输入是标有elgg-foot类的元素的子代.

That ensures that you only get the input named guid that is a child of the element labelled with class elgg-foot.

现代浏览器中的等效方法是本机的querySelectorAll方法:

The equivalent in modern browsers is the native querySelectorAll method:

document.querySelectorAll(".elgg-foot input[name='guid']")

或者您可以做自己的事:

or you can do what you have yourself:

var x = document.getElementsByClassName("elgg-foot")
var y = x.getElementsByTagName("input")[0];

假设您知道它始终是div中的第一个输入

Assuming you know it is always the first input within the div

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