Python-不支持的类型:范围和范围

问题描述

我在尝试运行脚本时遇到了一个奇怪的错误，该代码似乎是正确的，但是似乎python(3)不喜欢这部分:

I'm getting this strange error trying to run a script, the code appears to be correct but it seems python (3) didn't liked this part:

        def function(x):
                  if integer:
                    return int(x)
                else:
                    return x

            non_nil = randrange(21)
            d = dict([(randrange(101), Racional(coeff(randrange(-20,20)),
                                    coeff(choice(range(-30,0)+\
                                                 range(1,30)))))
                     for k in range(non_nil)])

我得到以下错误:

for k in range(non_nil)]) unsupported operand type(s) for +: 'range' and 'range'

我已经尝试将最后四行放在同一行中，但是python返回相同的错误.

I already tried to put the last four lines in a single one but python returns the same error.

推荐答案

这是因为Python 3 range不返回list，就像Python 2一样.此代码是为Python 2编写的.

This is because Python 3 range does not return a list, like Python 2. This code was written for Python 2.

此代码应更改:

range(-30,0) + range(1,30)

应更改为:

list(range(-30,0)) + list(range(1,30))

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