RangeError：bignum太大，无法转换为“ long”

问题描述

  num = 0000001000000000011000000000000010010011000011110000000000000000 
 for n in 0 ... num.length 
 temp = num [n] 
 dec = dec + temp *（2 **（数字长度-n-1））
结束
卖出dec 
  

当我在irb中运行此代码时，输​​出以下错误消息。当我在python中编译相同的逻辑时，它的工作绝对正常。我在Google上搜索了 RangeError：bignum太大，无法转换为'long'：但未找到相关答案。
请帮助我：(预先感谢。

 
 RangeError：bignum太大，无法转换为 long'
 from（irb）：4：in  *' 
 from（irb）：4：in irb_binding中的块'
 from（irb）：2：in 每个'
 from（irb ）：2 
来自C：/ Ruby193 / bin / irb：12：in''

解决方案

尝试一下

  num = 0000001000000000011000000000000010010011000011110000000000000000 
 dec = 0 
 for n in 0 ... num.length 
 temp = num [n] 
 dec = dec + temp.to_i *（2 **（numlength-n-1））
 end 
 put dec 
  

num = "0000001000000000011000000000000010010011000011110000000000000000"
for n in 0...num.length
   temp = num[n]
   dec =  dec + temp*(2**(num.length - n - 1))
end
puts dec

When i am running this code in irb the following error message is the output. and when i compiled the same logic in python it is working absolutely fine. I have Googled "RangeError: bignum too big to convert into `long': but didn't find the relevant answer.Please help me :( Thanks in Advance.

RangeError: bignum too big to convert into long'
        from (irb):4:in*'
        from (irb):4:in block in irb_binding'
        from (irb):2:ineach'
        from (irb):2
        from C:/Ruby193/bin/irb:12:in `'

解决方案

Try this

num = "0000001000000000011000000000000010010011000011110000000000000000"
dec = 0
for n in 0...num.length
   temp = num[n]
   dec =  dec + temp.to_i * (2**(num.length - n - 1))
end
puts dec

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