问题描述
我正在尝试在Google Analytics(分析)中找到如何确定用户访问一个部分中多个页面的会话数.例如:
用户访问以下页面:
此用户会话在/section-one/中将被视为一页以上.
用户访问以下页面:
此用户会话在/section-one/中不会被视为一页以上.
这在Google Analytics(分析)中是如何完成的?最好不要添加自定义事件.
杰伊，我认为您最好的解决方案是构建一个段，以便正确地知道在一个节中看到多少个会话确实看到了给定数量的页面. /p>
此解决方案将与具有允许的路径结构的页面一起使用，如您的示例中所述:/section-name/page.
因此，实现此目标的方法是创建一个细分使用条件的顺序".
该序列将使用以下逻辑使该段与条件匹配:如果会话查看了/section/中的页面，然后又查看了/section/中的另一个页面，则用户看到了该部分中的至少两个页面.
因此顺序将是:
添加您要跟踪的阈值的次数.
我看到的唯一缺陷是，如果用户看到两次相同的页面，则该页面将被视为符合条件.我想不出一条完美的规则来克服这个问题.我已经尝试了一些，但是我不能说它们是一个确定的解决方案.无论如何，据我所知，即使总是存在一定的误差余量，这种段也能很好地完成工作.
也许其他人知道一种更优雅的方法.
I'm trying to find in Google Analytics how to determine the number of sessions where a user visited more than one page within a section. For example:
User visits the following pages:
This user session would count as more than one page in /section-one/.
User visits the following pages:
This user session would not count as more than one page in /section-one/.
How is this done in Google Analytics? Preferably without adding custom events.
Jay, I think that your best solution is to build a segment in order to properly know how many sessions did see a given number of pages within a section.
This solution will work with a page that has a path structure that allows it, as described in your example: /section-name/page.
So, the way to achieve this is to create a Segment using a "Sequence" of conditions.
The sequence will make the segment match the conditions using the following logic: if session viewed page within /section/ and later viewed another page within /section/ that user saw at least two pages in that section.
So the sequence will be:
Add as many times as the threshold you want to track.
The only flaw I see is that if the user saw two times the same page, it will be counted as matching the condition. I can't figure a flawless rule yet to overcome that issue. I have tried some, but I cannot say they are a definite solution. Anyways, as long as I can see, this kind of segment does a good job, even if there will always be some error margin.
Maybe someone else knows a more elegant way to do this.
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