获取在magento中具有特定角色的用户

问题描述

有什么方法可以吸引Magento中具有特定角色的用户(例如员工)?我尝试过了

Is there any way to get users of a particular role (say staff) in Magento?I tried with this

$roles_users = Mage::getResourceModel('admin/roles_user_collection');

但是不知道如何为特定角色添加过滤器.

But dont know how to add filter for a particular role.

预先感谢

推荐答案

如果仔细看一下magento如何存储管理员角色和用户，您会更好地理解这一点.

If you look carefully at how magento stores admin roles and users, you would understand this better.

假设您创建角色staff，则magento将该角色存储在admin_role表中.创建新用户时，用户数据存储在admin_user表中，该表与admin_role表完全没有关联.但是，当您为该用户分配staff角色时，此分配本身会再次创建一个新的管理员角色.本质上，用户本身被视为管理员角色.

Say you create a role staff, magento stores this role in the admin_role table. When you create a new user, the user data is stored in the admin_user table, which has no association at all to the admin_role table. But, when you assign this user the role of staff, this assignment creates a new admin role in itself again. Essentially, the user itself is treated as an admin role.

这应该很好地工作:

$output = []; // just an array to hold all the users, you may not need this

// instance of the admin_role
$model = Mage::getModel('admin/role');

// fetch all roles with name of 'Staff', but get only the first item since two roles cannot have same name
$role = $model->getCollection()
    ->addFieldToFilter('role_name', ['eq' => 'Staff'])
    ->getFirstItem();

// check to make sure the role exists
if ($roleId = $role->getId())
{
    // get a collection of all the user roles having the Staff role id as a parent_id
    $staffUsers = $model->getCollection()
        ->addFieldToFilter('parent_id', ['eq' => $roleId]);

    // ensure the collection has size
    if ($staffUsers->getSize())
    {
        // loop through each object and get the user_id values
        foreach ($staffUsers as $staffUser)
        {
            // you can still check to make sure the user_id field is not null
            if ($staffUser->getUserId())
            {
                // get the user object and do anything with it
                $user = Mage::getModel('admin/user')->load($staffUser->getUserId());
                $output[$user->getId()] = $user->getFirstname() . " " . $user->getLastname();
            }
        }
    }
}


var_dump($output); die;

希望有帮助.

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