问题描述
我正在GraphQL上的演示项目.但是卡在这里.我想发送整个对象作为结果.我要发送的对象是:
I am working on a demo project on GraphQL. But stuck here. I want to send the whole object as result.The object which I want to send is:
exports.fakeDatabase = {
1: {
id: 1,
name: 'Abhay',
description:'This is Abhay\'s Database'
},
2: {
id: 2,
name:'Bankimchandra',
description: 'This is Bankimchandra\'s Database'
},
3: {
id: 3,
name:'chandu',
description: 'This is chandu\'s Database'
}
};
但是当我发送访问请求时,出现错误:
But when I am sending a request to access it I got Error:
Error: Can only create List of a GraphQLType but got: function GraphQLObjectType(config) {
_classCallCheck(this, GraphQLObjectType);
(0, _assertValidName.assertValidName)(config.name, config.isIntrospection);
this.name = config.name;
this.description = config.description;
if (config.isTypeOf) {
(0, _invariant2.default)(typeof config.isTypeOf === 'function', this.name + ' must provide "isTypeOf" as a function.');
}
this.isTypeOf = config.isTypeOf;
this._typeConfig = config;
}.
我的代码是-
schema.js:
const graphql = require('graphql');
var schema = {};
schema.getAllUser = new graphql.GraphQLObjectType({
name: 'getAllUser',
fields: {
data:{type:new graphql.GraphQLList(graphql.GraphQLObjectType)} // What should I do here to send the whole `fakeObject`
}
})
module.exports = schema;
Query.js:
const graphql = require('graphql');
const userType = require('../schemas/schemaUserType');
const fakeDatabase = require('../assets/database');
const config = require('../config/config');
var schema = {};
module.exports = schema;
const queryType = new graphql.GraphQLObjectType({
name: 'Query',
fields: {
getAllUser: {
type: userType.getAllUser,
args: {
}, resolve: function () {
return fakeDatabase.fakeDatabase;
}
}
}
});
schema.queryTypq1 = new graphql.GraphQLSchema({ query: queryType });
server.js:
var app = require('express')();
var graphHTTP = require('express-graphql');
const schema = require('./queries/queryType');
app.use('/graphql', graphHTTP({
schema: schema.queryTypq1,
graphiql: true
}));
app.listen(4000, () => { console.log('Server is running on port: 4000'); });
请让我明白如何发送对象fakeDatabase
Please make me understand what should i do to send the object fakeDatabase
推荐答案
-
第一个
fakeDatabase
应该是数组[]
,因为schema.getAllUser
第二步,您必须使用字段id
,name
和description
Second you have to create a GraphQLObjectType
with the fields id
, name
and description
可能是这样的...
may be something like this...
exports.fakeDatabase = [
{
id: 1,
name: 'Abhay',
description: 'This is Abhay\'s Database'
},
{
id: 2,
name: 'Bankimchandra',
description: 'This is Bankimchandra\'s Database'
},
{
id: 3,
name: 'chandu',
description: 'This is chandu\'s Database'
}
]
和GraphQLObjectType代表数据
and the GraphQLObjectType to represent the data
const fakeDatabaseType = new GraphQLObjectType({
name: 'fakeDatabase',
fields: {
id: { type: GraphQLID },
name: { type: GraphQLString },
description: { type: GraphQLString },
},
});
const graphql = require('graphql');
var schema = {};
schema.getAllUser = new graphql.GraphQLObjectType({
name: 'getAllUser',
fields: {
data: {
type: new graphql.GraphQLList(fakeDatabaseType),
resolve: function (obj) { /* obj is the parent object
containing the data passed from root query resolver */
return obj;
},
}
}
})
module.exports = schema;
const graphql = require('graphql');
const userType = require('../schemas/schemaUserType');
const fakeDatabase = require('../assets/database');
const config = require('../config/config');
var schema = {};
module.exports = schema;
const queryType = new graphql.GraphQLObjectType({
name: 'Query',
fields: {
getAllUser: {
type: schema.getAllUser,
args: {
}, resolve: function () {
return fakeDatabase; // passing the fake array
}
}
}
});
schema.queryTypq1 = new graphql.GraphQLSchema({ query: queryType });
希望这会有所帮助!
这篇关于错误:只能在GraphQL中创建GraphQLType的列表,但得到:函数GraphQLObjectType(config)?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!