本文介绍了值!不是akka.routing.Router的成员的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我一直在努力启动和运行一些Akka示例,并且遇到了一个给我带来很多麻烦的问题。对我来说,很奇怪的是,文档中直接出现了无法使用的代码。
I've been working on getting some Akka examples up and running and have run into an issue that is giving me quite a bit of trouble. What's so strange to me is that there is code coming straight out of the documentation that isn't working.
import akka.actor._
import akka.routing.{ ActorRefRoutee, RoundRobinRoutingLogic, Router, Broadcast }
object TransformationManager {
case class ProcessFile(fileIt:Iterator[String])
case class ProcessLines(lines:List[List[String]], last:Boolean = false)
case class LinesProcessed(lines:List[List[String]], last:Boolean = false)
case object WorkAvailable
case object WorkRequest
}
class TransformationManager extends Actor {
import TransformationManager._
val workChunkSize = 10
val workersCount = 10
def receive = {
case ProcessFile(fileIt) =>
var router = {
val routees = Vector.fill(workersCount) {
val r = context.actorOf(Props[SampleWorker])
context watch r
ActorRefRoutee(r)
}
Router(RoundRobinRoutingLogic(), routees)
}
router ! Broadcast(WorkAvailable) //error here !!!!!!!!!
}
}
在最后一行代码上,
router ! Broadcast(WorkAvailable)
我收到错误消息,
value ! is not a member of akka.routing.Router
我很茫然,为什么会这样呢?
I'm at a loss for why this isn't working.
推荐答案
在! >路由器。您使用 router.route
发送消息。
There's no !
on Router
. You use router.route
to send a message.
router.route(msg, sender())
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