从字符串中提取地址

问题描述

假设我有这个字符串：

<div>john doe is nice guy btw 8240 E. Marblehead Way 92808  is also</div>

或此字符串：

<div>sky being blue? in the world is true? 024 Brea Mall  Brea, California 92821 jackfroast nipping on the firehead</div>

我如何从其中一个字符串中提取地址？这会涉及到某种Regex，对吗？

How would I go about extracting the address from one of these strings? This would involve some sort of Regex, right?

我尝试在线寻找使用JavaScript或PHP的解决方案，但无济于事。
而且Stack Overflow上没有其他帖子（据我所知）提供了一个使用jQuery和/或Javascript和/或PHP的解决方案。 （最接近的是，该字符串中没有任何关于从字符串中提取邮政编码的代码。

I've tried looking online for a solution using JavaScript or PHP, but to no avail.And no other post here on Stack Overflow (as far as I know) provides a solution that uses jQuery and/or Javascript and/or PHP. (The closest is Parse usable Street Address, City, State, Zip from a string, which DOESN'T have any code in the thread about extracting a postal code from a string.

有人可以指点我正确的方向？我将如何在jQuery或JavaScript或PHP中实现这一目标？

Can somebody point me in the right direction? How would I go about accomplishing this in jQuery or JavaScript or PHP?

推荐答案

尝试了12个不同的字符串与你的相似，它运作得很好：

Tried this on twelve different strings that were similar to yours and it worked just fine:

function str_to_address($context) {

    $context_parts = array_reverse(explode(" ", $context));
    $zipKey = "";
    foreach($context_parts as $key=>$str) {
        if(strlen($str)===5 && is_numeric($str)) {
            $zipKey = $key;
            break;
        }
    }

    $context_parts_cleaned = array_slice($context_parts, $zipKey);
    $context_parts_normalized = array_reverse($context_parts_cleaned);
    $houseNumberKey = "";
    foreach($context_parts_normalized as $key=>$str) {
        if(strlen($str)>1 && strlen($str)<6 && is_numeric($str)) {
            $houseNumberKey = $key;
            break;
        }
    }

    $address_parts = array_slice($context_parts_normalized, $houseNumberKey);
    $string = implode(' ', $address_parts);
    return $string;
}

这假设门牌号至少为两位数，且不大于6位。这也假定邮政编码不是扩展形式（例如12345-6789）。然而，这可以很容易地修改以适应这种格式（正则表达式在这里是一个很好的选择，类似于（\d {5} -\d {4}）。

This assumes a house number of at least two digits, and no greater than six. This also assumes that the zip code isn't in the "expanded" form (e.g. 12345-6789). However this can be easily modified to fit that format (regex would be a good option here, something like (\d{5}-\d{4}).

但是使用正则表达式来解析用户输入的数据......这里不是一个好主意，因为我们只是不知道用户将输入什么，因为有（可以假设）没有验证。

But using regex for parsing user-inputted data... Not a good idea here, because we just don't know what a user is going to input because there were (as one can assume) no validations.

遍历代码和逻辑，从上下文创建数组开始并抓住zip：

Walking through the code and logic, starting with creating the array from the context and grabbing the zip:

// split the context (for example, a sentence) into an array,
// so we can loop through it.
// we reverse the array, as we're going to grab the zip first.
// why? we KNOW the zip is 5 characters long*.
$context_parts = array_reverse(explode(" ", $context));

// we're going to store the array index of the zip code for later use
$zipKey = "";

// foreach iterates over an object given the params,
// in this case it's like doing...
// for each value of $context_parts ($str), and each index ($key)
foreach($context_parts as $key=>$str) {

    // if $str is 5 chars long, and numeric...
    // an incredibly lazy check for a zip code...
    if(strlen($str)===5 && is_numeric($str)) {
        $zipKey = $key;

        // we have what we want, so we can leave the loop with break
        break;
    }
}

做一些整理，以便我们有一个更好的服装对象房屋号码来自

Do some tidying so we have a better object to garb the house number from

// remove junk from $context_array, since we don't
// need stuff after the zip
$context_parts_cleaned = array_slice($context_parts, $zipKey);

// since the house number comes first, let's go back to the start
$context_parts_normalized = array_reverse($context_parts_cleaned);

然后让我们使用与邮政编码相同的基本逻辑来获取门牌号码：

And then let's grab the house number, using the same basic logic that we did the zip code:

$houseNumberKey = "";
foreach($context_parts_normalized as $key=>$str) {
    if(strlen($str)>1 && strlen($str)<6 && is_numeric($str)) {
        $houseNumberKey = $key;
        break;
    }
}

// we probably have the parts we for the address.
// let's do some more cleaning
$address_parts = array_slice($context_parts_normalized, $houseNumberKey);

// and build the string again, from the address
$string = implode(' ', $address_parts);

// and return the string
return $string;

这篇关于从字符串中提取地址的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！