本文介绍了让python脚本运行一分钟的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在做一个小项目,其中脚本用于监视用户的键盘输入,我只希望脚本运行 1 分钟.那一分钟过去后,我想要输入的最终打印语句并终止脚本.time.sleep 函数在这里不是一个可行的选择,因为我想更新变量并接收每个动作的输出,而使用 sleep 只会延迟每个输入.
I'm working on a small project where the script is to monitor user's keyboard inputs and I only want the script to run for a duration of 1 minute. After that minute has passed, I want a final print statement of the inputs and to terminate the script. The time.sleep function is not a viable choice here since I want to update variables and receive output for every action, and using sleep will only delay each input.
from pynput import keyboard
word_counter = 0
def on_press(key):
global word_counter
try:
print('alphabet key {} pressed'.format(key.char))
except AttributeError:
if key == keyboard.Key.space:
word_counter += 1
print(word_counter)
elif key == keyboard.Key.esc:
return False
print('special key {} pressed'.format(key))
with keyboard.Listener(on_press=on_press) as listener:
listener.join()
# After a minute, this will be the final output and the program will terminate
print('You typed a total of {} words in a minute'.format(word_counter))
推荐答案
这就是答案:
from pynput import keyboard
import threading, time
word_counter = 0
def background():
def on_press(key):
global word_counter
try:
print('alphabet key {} pressed'.format(key.char))
except AttributeError:
if key == keyboard.Key.space:
word_counter += 1
print(word_counter)
elif key == keyboard.Key.esc:
return False
print('special key {} pressed'.format(key))
with keyboard.Listener(on_press=on_press) as listener:
listener.join()
def wait():
time.sleep(60)
background = threading.Thread(name = 'background', target = background)
background.start()
wait()
# After a minute, this will be the final output and the program will terminate
print('You typed a total of {} words in a minute'.format(word_counter))
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