问题描述
一些标准的 iomanip
函数接受一个参数。
Some of the standard iomanip
functions take take a parameter.
我想知道如何是完成了,例如,我可以做一些类似的功能吗?这真的是我需要的解决方案,但我不知道该怎么做。
I'd like to know how this is accomplished, for instance, can I do something similar with a function? That's really the solution that I needed for this answer, but I couldn't figure out how to do this.
当我查找 setw
函数的定义时,例如在它将返回类型列为未指定,并且它也只列出一个参数,而不是也采取一个流&
参数。
When I looked up the definition for setw
function for example in http://en.cppreference.com it lists the return type as "unspecified", and it also only lists one argument, rather than also taking a stream&
parameter. How does this work?
推荐答案
这里是一个用户定义的操纵器的简单示例,它使用一个类定义了一个参数:
Here is a simple example of a user-defined manipulator that takes one parameter defined using a class:
#include <iostream>
class putX // injects some `X`s into the stream
{
std::size_t _n;
public:
explicit putX(std::size_t n): _n(n) {}
std::size_t getn() const {return _n;}
friend std::ostream& operator<<(std::ostream& os, const putX& obj)
{
std::size_t n = obj.getn();
for (std::size_t i = 0; i < n; ++i)
os << 'X';
return os;
}
};
int main()
{
std::cout << putX(10) << " test " << putX(10);
}
不带参数的操纵器可以简单地实现为
Manipulators that take no parameters can simply be implemented as
std::ostream& custom_manip(std::ostream& os) { // do something with os and return os;}
这是因为 basic_ostream :: operator<<
有一个重载,它接受一个指针函数 std :: ostream& (* fp)(std :: ostream&)
为其右手侧(例如,操纵器)
That's because basic_ostream::operator<<
has an overload that takes a pointer-to-function std::ostream& (*fp)(std::ostream&)
as its right hand side (e.g., a manipulator)
PS: C ++标准库描述了操纵器/自定义操纵器是如何工作的很详细,见第。 15.6.3 用户定义的操纵符
PS: The C++ Standard Library by N. Josuttis describes how manipulators/custom manipulators work in great detail, see Sec. 15.6.3 User-Defined Manipulators
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