本文介绍了SQL Inner用订单加入客户的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如果我有两张桌子(其中一个客户,其信息包括地址,姓名,电子邮件等)和另一个订单(订单号,发货日期,订购该商品的客户名称),我如何显示有少于3个订单的客户的电子邮件?
我知道我必须使用内部连接和一些别名,但我不知道如何继续。 / b>
谢谢!
到目前为止:
选择customer.email
从customer作为cust
INNER JOIN(选择customer_id,sum(line_qty)AS从订单中总计
ON ON cust。 customer_id = o.customer_id
where total =(SELECT total FROM(select customer_id,sum(line_qty)AS total
from order as o cust.customer_id = o.customer_id
)as sub);
解决方案
这:
SELECT c.email
FROM customer AS c
LEFT OUTER JOIN命令AS o ON c .customer_id = o.customer_id
GROUP BY c.email
HAVING SUM(o.line_qty)< 3
if I have a two tables (one of customers, with their information including address, name, emails etc) and another of orders (with order number, shipping date, customer name who ordered that item), how could I show the email of the customers who have less than 3 orders?
I know I have to use an inner join and some alias's, but i'm not sure how to proceed.
Thanks!
what I have so far:
SELECT customer.email
FROM customer as cust
INNER JOIN (select customer_id, sum(line_qty) AS total
from orders as o ON cust.customer_id = o.customer_id
where total = (SELECT total < 3
FROM (select customer_id, sum(line_qty) AS total
from orders as o ON cust.customer_id = o.customer_id
) as sub);
解决方案
Try this:
SELECT c.email
FROM customer AS c
LEFT OUTER JOIN orders AS o ON c.customer_id = o.customer_id
GROUP BY c.email
HAVING SUM(o.line_qty) < 3
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