问题描述
我需要将字符指针转换为w_char *,以便使用ParseNetworkString()。我已经尝试找到解决方案,我自己,虽然我找到一个解决方案,有一个问题,阻止我使用它:
b1naryatr0phy在另一篇文章:
std :: wstring name(LSteve Nash);
const wchar_t * szName = name.c_str();
这对我来说几乎是有效的,除了我不能只传递字符串显式性并不总是相同的,这意味着我不能把它在引号。如果我用一个函数调用替换参数,那么第一行给我一个错误(例如:std :: wstring name(LgetIpAddress());我试过std :: wstring name(L+ getIpAddress );,认为它只是需要一个引号在L后,但是不工作,任何建议?
谢谢!
链接到其他帖子:
PS对不起,只是为了澄清,getIpAddress返回一个字符指针
解决方案 getIpAddress / code>?
这是一个代码片段,显示如何将字符串
转换为 wstring
(使用标准C ++ 11,无错误检查):
wstring to_wstring string const& str)
{
size_t len = mbstowcs(nullptr,& str [0],0);
if(len == -1)//无效的源str,throw
wstring wstr(len,0);
mbstowcs(& wstr [0],& str [0],wstr.size());
return wstr;
}
I need to convert character pointer to a w_char * in order to use ParseNetworkString(). I've tried finding solutions to this myself, and while I have found one solution, there is one issue which blocks me from using it:
b1naryatr0phy said in an other post:
std::wstring name( L"Steve Nash" );
const wchar_t* szName = name.c_str();
this almost works for me, except that I can't just pass the string explicity, as its value is not always going to be the same, meaning I can't just put it in quotes. If I replace the parameter with a function call, then the first line gives me an error (example: std::wstring name(LgetIpAddress()); I've tried std::wstring name(L" " + getIpAddress() + " "); , thinking that it just needs a quotation mark after the L, but that doesn't work either.. any suggestions?
Thanks! :)
Extra Kudos to whoever can answer this!
link to other post: I want to convert std::string into a const wchar_t *
P.S. Sorry, just to clarify, getIpAddress returns a character pointer
解决方案 What's the type of getIpAddress()
?
Here's a snippet showing how to convert a string
to a wstring
(using standard C++11, no error checking):
wstring to_wstring(string const& str)
{
size_t len = mbstowcs(nullptr, &str[0], 0);
if (len == -1) // invalid source str, throw
wstring wstr(len, 0);
mbstowcs(&wstr[0], &str[0], wstr.size());
return wstr;
}
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