问题描述
我需要在 JSON 中为我的 REST OSB 12c 代理发送 XML,如下所示:
{"登录": "jstein","identityContext": "jazn.com","taskId": "字符串",有效载荷":{any_0":{"any_01": "<afastamento xmlns:ns1='http://www.tjsc.jus.br/soa/schemas/comagis/AfastamentoMagistrado' xsi:type='def: AfastamentoMagistradoType' xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' xmlns='http://xmlns.oracle.com/bpel/workflow/task'><ns1:Magistrado>719</ns1:Magistrado><ns1:Status>初始</ns1:Status><ns1:Vaga>8770</ns1:Vaga><ns1:Tipo>Licenca Nojo</ns1:Tipo><ns1:PeriodoReferencia/><ns1:DataIncialSolicitada>2015-10-10</ns1:DataIncialSolicitada><ns1:DataFinalSolicitada>2015-11-05</ns1:DataFinalSolicitada></afastamento>"}},结果":开始"}
OSB 12c 将错误发回给我:
"errorMessage" : "ORABPEL-15235\n\n翻译失败.\n无法翻译JSON 到 XML.org.codehaus.jackson.JsonParseException:非法未加引号字符 ((CTRL-CHAR, code 10)): 必须使用反斜杠转义为包含在字符串值中\n [来源:java.io.BufferedReader@7db921c7;线:7,列:619]\n传入的数据不符合 NXSD 架构.请更正问题.\n"
我正在 JSONLint 测试我的 JSON 请求,它总是给我关于用 <
开始一个字符串的错误:
第 7 行解析错误:"any_01": "<afastamento xmlns:-----------^期待 'STRING, 'NUMBER, 'NULL', 'TRUE', FALSE', '{', '['
No,文字换行符 (CTRL-CHAR, code 10
) 和换行符是控制字符在 JSON 字符串中
XML 不需要元素之间的换行符.您可以简单地删除它们,将多行 XML 文档更改为等效的单行 XML 文档,该文档可以毫无问题地作为 JSON 字符串传递.或者,您可能需要考虑转义换行符 \n
,或者更一般地说,转义整个字符串:
I need to send XML inside a JSON for my REST OSB 12c Proxy as follow:
{
"login": "jstein",
"identityContext": "jazn.com",
"taskId": "string",
"payload": {
"any_0": {
"any_01": "<afastamento xmlns:ns1='http: //www.tjsc.jus.br/soa/schemas/comagis/AfastamentoMagistrado' xsi:type='def: AfastamentoMagistradoType' xmlns:xsi='http: //www.w3.org/2001/XMLSchema-instance' xmlns='http: //xmlns.oracle.com/bpel/workflow/task'>
<ns1:Magistrado>719</ns1:Magistrado>
<ns1:Status>Inicial</ns1:Status>
<ns1:Vaga>8770</ns1:Vaga>
<ns1:Tipo>Licenca Nojo</ns1:Tipo>
<ns1:PeriodoReferencia/>
<ns1:DataInicialSolicitada>2015-10-10</ns1:DataInicialSolicitada>
<ns1:DataFinalSolicitada>2015-11-05</ns1:DataFinalSolicitada>
</afastamento>"
}
},
"outcome": "Start"
}
The OSB 12c send me back the error:
I am testing my JSON request at JSONLint, and it always gives me the error about start a String with <
:
No, literal line feeds (CTRL-CHAR, code 10
) and newlines are control characters that are not allowed within a JSON string:
XML does not require the line feeds between elements. You can simply remove them, changing your multi-line XML document to an equivalent single-line XML document that will be able to be passed as a JSON string without problem. Or, you may want to consider escaping the line feeds \n
, or more generally, escaping the entire string:
- How should I escape strings in JSON? [Java]
- In C# how to encode XML to output it inside JSON in the JavaScriptpart of a page
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