当数组已经包含JSON字符串时，将数组转换为JSON字符串

问题描述

我有一个包含JSON字符串的数组.

I have an array that contains a JSON string.

Array
(
    [0] => Array
        (
            [name] => Original
            [nutrients] => {"calories":{"value":2500,"operator":2},"protein":{"value":500,"operator":1},"carbs":{"value":200,"operator":0},"fat":{"value":50,"operator":0},"sugar":{"value":1,"operator":2}}
        )

    [1] => Array
        (
            [name] => Rest
            [nutrients] => {"calories":{"value":5000,"operator":2},"sugar":{"value":10,"operator":2}}
        )

)

我想将整个数组转换为JSON字符串

I want to turn the whole array into a JSON string

echo json_encode($array);

但这会在所有引号前面引发\

But this throws a \ in front of all quotes

[{"name":"Original","nutrients":"{\"calories\":{\"value\":2500,\"operator\":2},\"protein\":{\"value\":500,\"operator\":1},\"carbs\":{\"value\":200,\"operator\":0},\"fat\":{\"value\":50,\"operator\":0},\"sugar\":{\"value\":1,\"operator\":2}}"},{"name":"Rest","nutrients":"{\"calories\":{\"value\":5000,\"operator\":2},\"sugar\":{\"value\":10,\"operator\":2}}"}]

出现此问题是因为营养值已经是JSON字符串.

This problem comes about because the nutrients value is already a JSON string.

当数组已经包含JSON字符串且引号前没有斜杠时，如何将其转换为JSON字符串?

How can I convert an array into a JSON string when it already contains JSON strings, while having no slashes in front of the quotes?

推荐答案

如果要将JSON值保留为字符串；那么，你就不能，而且你不应该能够！

If you want to preserve the JSON values as strings; then, you can't, and you shouldn't be able to!

如果您的数组已经包含一些JSON值(其中将带有一些引号:")，并且您想将该数组编码为JSON字符串，则引号必须正确地逃脱，正确地得到什么；否则，由于缺少引号匹配，整个JSON字符串将被破坏.

If your array already contains some JSON values (in which they'll have some quotation marks: ") and you want to encode that array into a JSON string, then the quotation marks must be properly escaped, what you get correctly; otherwise, the entire JSON string will be corrupt because of miss-quotation-mark matches.

这是因为"在JSON中具有特殊含义，但是\"表示双引号字符" 不是"的特殊标记；例如，从有效的JSON字符串中删除反斜杠肯定会导致一些语法错误:

That's because the " has a special meaning in JSON, but the \" means the "double quotation mark character" not the special token of "; for example, removing the backslashes from the valid JSON string causes some syntax errors for sure:

$json = '[{"name":"Original","nutrients":"{\"calories\":{\"value\":2500,\"operator\":2},\"protein\":{\"value\":500,\"operator\":1},\"carbs\":{\"value\":200,\"operator\":0},\"fat\":{\"value\":50,\"operator\":0},\"sugar\":{\"value\":1,\"operator\":2}}"},{"name":"Rest","nutrients":"{\"calories\":{\"value\":5000,\"operator\":2},\"sugar\":{\"value\":10,\"operator\":2}}"}]';
$json_noBackslashes = str_replace('\\', '', $json);
$json_decoded = json_decode($json_noBackslashes);
echo json_last_error_msg(); // Syntax error

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