生成随机布尔值的最快方法

问题描述

因此，有几种方法可以在C#中创建随机布尔值:

So there is several ways of creating a random bool in C#:

• 使用Random.Next():rand.Next(2) == 0
• 使用Random.NextDouble():rand.NextDouble() > 0.5

• Using Random.Next(): rand.Next(2) == 0
• Using Random.NextDouble(): rand.NextDouble() > 0.5

真的有区别吗?如果是这样，哪一个实际上具有更好的性能?还是有我没有看到的另一种方法，它可能甚至更快?

Is there really a difference? If so, which one actually has the better performance? Or is there another way I did not see, that might be even faster?

推荐答案

第一个选项-rand.Next(2)在后台执行以下代码:

The first option - rand.Next(2) executes behind the scenes the following code:

if (maxValue < 0)
{
    throw new ArgumentOutOfRangeException("maxValue",
        Environment.GetResourceString("ArgumentOutOfRange_MustBePositive", new object[] { "maxValue" }));
}
return (int) (this.Sample() * maxValue);

，并在第二个选项-rand.NextDouble():

return this.Sample();

因为第一个选项包含maxValue验证，乘法和强制转换，所以第二个选项可能更快.

Since the first option contains maxValue validation, multiplication and casting, the second option is probably faster.

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