Facebook的SDK - 而invating朋友错误ID

问题描述

我想发邀请给用户的Facebook好友。对于我用下面的code：

I want to send invites to user's facebook friends. For that I use the following code:

String KEY_MESSAGE = "message";

    Bundle params = new Bundle();
    params.putString(KEY_MESSAGE, "Learn how to make your Android apps social");

    WebDialog requestsDialog = (new WebDialog.RequestsDialogBuilder(context, Session.getActiveSession(), params))
            .setOnCompleteListener(new WebDialog.OnCompleteListener() {

                @Override
                public void onComplete(Bundle values, FacebookException error) {
                    if (error == null) {

                        Log.w(TAG, "Posted successfully. Values: " + values);
                        Toast.makeText(context, "Success", Toast.LENGTH_SHORT).show();

                    } else if (error instanceof FacebookOperationCanceledException) {
                        Log.e(TAG, "Post canceled");
                    } else {
                        Log.e(TAG, "Strange error: " + error);
                        Toast.makeText(context, "Error", Toast.LENGTH_SHORT).show();
                    }
                }

            })
            .build();
    requestsDialog.show();

我的应用程序显示请求对话框。我选择一个朋友，按下发送按钮。然后我发现通过这个朋友的ID。我的日志：

My app shows request dialog. I select one friend and push "Send" button. Then I find out this friend id via this website. My logs:

Posted successfully. Values: Bundle[{to[0]=<unknown-friend-id>, request=388113714696190}]

朋友，我想邀请bу不recive任何邀请。而他的ID不等于未知朋友-ID。它为什么是错误的？我没有想法

Friend that I want to bу invited do not recive any invites. And his id do not equals "unknown-friend-id". Why can it be wrong? I've got no ideas

P.S。不明-朋友-ID是一组数字。这是某人的ID。我决定不公布。不看丢的意见。他们是问题的priveous版本。

P.S. "unknow-friend-id" is set of numbers. It is someones id. I decided not to publish it. And don't look throw the comments. They are for priveous version of the question.

推荐答案

感谢@WizKid。正如他所说的：

Thanks @WizKid. As he said:

它不工作，因为你的应用程序还没有一个帆布的版本。欲了解更多信息，请阅读

It doesn't work because your app hasn't a canvas version. For more information you should read this

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