问题描述
有以下代码:
#include <stdio.h>
#include <curl/curl.h>
int main(void){
CURL *curl;
CURLcode res;
curl = curl_easy_init();
if(curl == NULL)
return 0;
curl_easy_setopt(curl, CURLOPT_URL, "https://example.com/getAccessAttributes?id=1");
res = curl_easy_perform(curl);
if(res != CURLE_OK) {
fprintf(stderr, "Error: %s\n", curl_easy_strerror(res));
return 0;
}
curl_easy_cleanup(curl);
return 0;
}
如果您从动态链接库中收集所有内容,则一切正常:
Everything works fine if you collect it from the dynamic link library:
gcc test.c -lcurl -o test
现在我想提出一个静态程序:
Now I want to raise a static program:
gcc test.c /tmp/curl/lib/libcurl.a -static -lcurl -lssl -lcrypto -ldl -lm -lz -DCURL_STATICLIB -I/tmp/curl/include -o test
他走错了路
仅当您指定主机IP地址而不是example.com时,该程序才有效.否则,程序将无法解析域名:
The program works only if you specify a host ip address and not example.com.Otherwise the program can not resolve the domain name:
$ ./test
Error: Couldn't resolve host name
如何解决名称解析问题?谢谢!
How can I solve the problem of name resolution? Thanks!
P.S.静态libcurl我收集了以下方法:
P.S.Static libcurl I collected the following method:
wget http://curl.haxx.se/download/curl-7.44.0.tar.lzma
tar xf curl-7.44.0.tar.lzma
cd curl-7.44.0
./configure --disable-shared --enable-static --prefix=/tmp/curl --disable-ldap --disable-sspi --without-librtmp --disable-ftp --disable-file --disable-dict --disable-telnet --disable-tftp --disable-rtsp --disable-pop3 --disable-imap --disable-smtp --disable-gopher --disable-smb --without-libidn
make && make install
推荐答案
动态libcurl的外观如下.
This is how it looks with dynamic libcurl.
$ ldd test
linux-vdso.so.1 (0x00007ffcca3aa000)
libcurl.so.4 => /usr/lib64/libcurl.so.4 (0x00007f5536ed6000)
libc.so.6 => /lib64/libc.so.6 (0x00007f5536b3e000)
libssl.so.1.0.0 => /usr/lib64/libssl.so.1.0.0 (0x00007f55368d3000)
libcrypto.so.1.0.0 => /usr/lib64/libcrypto.so.1.0.0 (0x00007f5536503000)
libz.so.1 => /lib64/libz.so.1 (0x00007f55362ed000)
/lib64/ld-linux-x86-64.so.2 (0x00007f5537138000)
libdl.so.2 => /lib64/libdl.so.2 (0x00007f55360e9000)
如果只想静态链接curl,请不要使用-static.只需将libcurl.a添加为目标文件之一或使用-lcurl,就无需指定两次.之后
If you want to link only curl statically, do not use -static. Just add libcurl.a as one of the objects files or use -lcurl, you don't need to specify it twice.After
gcc test.c curl-7.44.0/lib/.libs/libcurl.a -lssl -lcrypto -ldl -lm -lz -DCURL_STATICLIB -o test
你会得到
$ ldd test
linux-vdso.so.1 (0x00007ffd9a0a7000)
libssl.so.1.0.0 => /usr/lib64/libssl.so.1.0.0 (0x00007f947cc7e000)
libcrypto.so.1.0.0 => /usr/lib64/libcrypto.so.1.0.0 (0x00007f947c8ae000)
libdl.so.2 => /lib64/libdl.so.2 (0x00007f947c6aa000)
libm.so.6 => /lib64/libm.so.6 (0x00007f947c3b1000)
libz.so.1 => /lib64/libz.so.1 (0x00007f947c19b000)
libc.so.6 => /lib64/libc.so.6 (0x00007f947be03000)
/lib64/ld-linux-x86-64.so.2 (0x00007f947cee9000)
-static表示您要全部静态链接.然后,您需要将所有库准备为静态,结果将是:
-static means that you want link all statically. Then you need all libraries prepared as static and the result will be:
$ ldd test
not a dynamic executable
这篇关于如何使用静态libcurl编译程序?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!