本文介绍了猜数字 - 无限循环时坏读的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 29岁程序员，3月因学历无情被辞！ 所以我使这个猜数字游戏在c + +，看起来像这样：So I am making this Guess the number game in c++ that looks like this:#include <iostream>#include <cstdlib>#include <ctime>using namespace std;int main(){ srand(time(0)); int secretNumber = rand() % 100 + 1; //Generate "Random number" int nbrOfGuesses = 0; int userInput; cout<<"\t************************************"<<endl; cout<<"\t* *"<<endl; cout<<"\t* Guess the number! *"<<endl; cout<<"\t* *"<<endl; cout<<"\t************************************"<<endl; cout<<endl; cout << "Try to find the secret int number: " << endl; //While input is good while(cin.good()) { //Do this do { cin>>userInput; nbrOfGuesses++; if (userInput>secretNumber) cout << "Smaller!\n"; else if(userInput<secretNumber) cout << "Bigger!\n"; // <-- Infinite loop here when you enter something other than an integer else //Also using this as a backup of (cin.good()) cout << "Something went wrong with the read"; break; } while(userInput!=secretNumber); cout << "\nCongratulations! You got it in " << nbrOfGuesses << " guesses\n"; } system("pause"); return 0;} *对不起，如果代码是非常优雅的*Sorry if the code is note very elegant正如你所看到的，代码工作得很好，直到你输入一个随机的符号'&'或'j'或任何不是一个整数的其他...然后它循环在cout& <Bigger！;As you can see, the code works great until you enter a random caracter like '&' or 'j' or anything else that isn't an integer...Then it loops at cout<<"Bigger!";所以我的问题是：是什么原因造成这种情况？So my question is: What is causing this?推荐答案检查此帖，这是大致相同的问题。总结：Check this post, it is about the same problem. To summarize:cin>>userInput;if (cin.fail()) { cout<<"Invalid Entry, please try again."<<endl; cin.clear(); cin.ignore(numeric_limits<streamsize>::max(), '\n');}感谢ildjarn指向缺少的忽略语句，在帖子中清楚提到我链接到!!Thanks ildjarn for pointing the missing ignore statement, I missed that part even though its clearly mentioned in the post I linked to!! 这篇关于猜数字 - 无限循环时坏读的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！ 上岸，阿里云！
