本文介绍了在 Node.js 退出之前执行清理操作的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想告诉 Node.js 总是在它退出之前做一些事情,无论出于什么原因 - +、异常或任何其他原因.
I want to tell Node.js to always do something just before it exits, for whatever reason — +, an exception, or any other reason.
我试过了:
process.on('exit', function (){
console.log('Goodbye!');
});
我启动了这个进程,杀死了它,什么也没发生.我再次启动它,按下+,仍然没有任何反应......
I started the process, killed it, and nothing happened. I started it again, pressed +, and still nothing happened...
推荐答案
更新:
您可以为 process.on('exit')
注册一个处理程序,并在任何其他情况下(SIGINT
或未处理的异常)调用 process.exit()
UPDATE:
You can register a handler for process.on('exit')
and in any other case(SIGINT
or unhandled exception) to call process.exit()
process.stdin.resume();//so the program will not close instantly
function exitHandler(options, exitCode) {
if (options.cleanup) console.log('clean');
if (exitCode || exitCode === 0) console.log(exitCode);
if (options.exit) process.exit();
}
//do something when app is closing
process.on('exit', exitHandler.bind(null,{cleanup:true}));
//catches ctrl+c event
process.on('SIGINT', exitHandler.bind(null, {exit:true}));
// catches "kill pid" (for example: nodemon restart)
process.on('SIGUSR1', exitHandler.bind(null, {exit:true}));
process.on('SIGUSR2', exitHandler.bind(null, {exit:true}));
//catches uncaught exceptions
process.on('uncaughtException', exitHandler.bind(null, {exit:true}));
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