排除参数化测试类中的非参数测试

问题描述

JUnit中是否有任何注释可以排除参数化测试类中的非参数测试?

Is there any annotation in JUnit to exclude a non param test in parameterized test class?

推荐答案

JUnit 5

从Junit 5.0.0开始，您现在可以使用@ParameterizedTest注释测试方法.因此，不需要内部类.除了ValueSource之外，还有很多方法可以为参数化测试提供参数，如下所示.有关详细信息，请参见官方junit用户指南. :

JUnit 5

As of Junit 5.0.0 you can now annotate your test methods with @ParameterizedTest. So no need for inner classes. There are many ways to supply the arguments to the parameterized test apart from ValueSource as shown below. See the official junit user guide for details:

import org.junit.jupiter.api.Test;
import org.junit.jupiter.api.ParameterizedTest;
import org.junit.jupiter.params.provider.ValueSource;

public class ComponentTest {

    @ParameterizedTest
    @ValueSource(strings = { "racecar", "radar", "able was I ere I saw elba" })
    public void testCaseUsingParams(String candidate) throws Exception {
    }

    @Test
    public void testCaseWithoutParams() throws Exception {
    }
}

JUnit 4

如果您仍在使用Junit 4(我在v4.8.2上进行了测试)，则可以将封闭式流道与内部类和参数化流道一起使用:

JUnit 4

If you are still using Junit 4 (I tested with v4.8.2) you can use the Enclosed runner in conjunction with inner classes and the Parameterized runner:

import org.junit.Test;
import org.junit.experimental.runners.Enclosed;
import org.junit.runner.RunWith;
import org.junit.runners.Parameterized;

@RunWith(Enclosed.class)
public class ComponentTest {

    @RunWith(Parameterized.class)
    public static class ComponentParamTests {

        @Parameters
        ...

        @Test
        public void testCaseUsingParams() throws Exception {
        }
    }

    public static class ComponentSingleTests {

        @Test
        public void testCaseWithoutParams() throws Exception {
        }
    }
}

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