设置数组所有值的最快方法?

问题描述

我有一个 char []，我想将每个索引的值设置为相同的 char 值.
有一个显而易见的方法(迭代):

I have a char [], and I want to set the value of every index to the same char value.
There is the obvious way to do it (iteration):

  char f = '+';
  char [] c = new char [50];
  for(int i = 0; i < c.length; i++){
      c[i] = f;
  }

但我想知道是否有一种方法可以利用 System.arraycopy 或等效的东西来绕过迭代的需要.有没有办法做到这一点?

But I was wondering if there's a way that I can utilize System.arraycopy or something equivalent that would bypass the need to iterate. Is there a way to do that?

来自 Arrays.java

public static void fill(char[] a, int fromIndex, int toIndex, char val) {
        rangeCheck(a.length, fromIndex, toIndex);
        for (int i = fromIndex; i < toIndex; i++)
            a[i] = val;
    }

这是完全相同的过程，这表明可能没有更好的方法来做到这一点.
+1 给所有建议 fill 的人 - 你们都是对的，谢谢.

This is exactly the same process, which shows that there might not be a better way to do this.
+1 to everyone who suggested fill anyway - you're all correct and thank you.

推荐答案

Try Arrays.fill(c, f) : 数组 javadoc

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