问题描述
我正在一个小项目中工作,而不是所有编程方面的专家。
有一定要求我必须从单个文本中保存条目框到一个XML文件,并在需要时将它们返回到另一个多行文本框。
一行中的每个条目。
IE
toolstriptextbox_1条目1 = abc
条目2 = xyz
等..
我的代码(下面)设法将条目保存到XML文件,但它会复制相同的第一个条目,而不是每次文本框中的新条目更改时捕获不同的条目。
这是代码的一部分。涉及此操作。
\\保存部分\\创建它作为一个单独的类。
命名空间HW_Browser
{
公共类SaveXml
{
public static void Saveurl(object myurl,string filename)
{
XmlSerializer sr = new XmlSerializer(myurl.GetType());
TextWriter writer = new StreamWriter(filename );
sr.Serialize(作家,myurl);
writer.Close();
}
}
}
+++++++++++++++++++++++++++++++++++++++++ ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++这确实是这样,但我知道\\it的单独类也处理XML文件的读写。
namespace HW_Browser
{
public class browsinghistory
{
private string entry1;
private string entry2;
private string entry3;
private string entry4;
public string Entry1
{
get { return entry1; }
set {entry1 = value ; }
}
public string Entry2
{
get { return entry2; }
set {entry2 = value ; }
}
public string Entry3
{
get { return entry3; }
set {entry3 = value ; }
}
public string Entry4
{
get { return entry4; }
set {entry4 = value ; }
}
}
}
+++++++++++++++++++++++++++++++++ ++++++++++++++++++++++++++++++++++++++++++++++++++++++++ code-keyword> 其中它被保存到XML文件\\由按钮触发单击
尝试
{
browhistory his = new 浏览记录();
his.Entry1 = toolStripTextBox1.Text;
his.Entry2 = toolStripTextBox1.Text;
his.Entry3 = toolStripTextBox1.Text;
his.Entry4 = toolStripTextBox1.Text;
SaveXml.Saveurl(他的, history.xml);
}
catch (Exception ex)
{
MessageBox.Show(ex 。信息); b
$ b +++++++++++ +++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ -keyword> 其中 XML文件应该将值显示回另一个多行文本框。
if (File.Exists( history.xml))
{
XmlSerializer xs = new XmlSerializer( typeof运算(browsinghistory));
FileStream read = new FileStream( history .xml,FileMode.Open,FileAccess.Read,FileShare.Read);
browhistory his =(browsinghistory)xs.Deserialize(read);
textBox1.Text = his.Entry1;
textBox1.Text = his.Entry2;
textBox1.Text = his.Entry3;
textBox1.Text = his.Entry4;
read.Close();
}
I am working in a small project , not at all expert in programming.
There is a certain requirement where in I have to save entries from a single text box to an XML file and return them back when required to a different Multi-line text box.
Each entry in a line.
IE
toolstriptextbox_1 Entry 1 = abc
Entry 2 = xyz
etc..
My code (below) managed to save entries to the XML file, however it duplicates the same first entry rather than capturing different entries each time a new entry in the text box changes.
Here is the portion of the code. that involves this operation.
\\ The saving parts\\ created it as a separate class.
namespace HW_Browser
{
public class SaveXml
{
public static void Saveurl(object myurl, string filename)
{
XmlSerializer sr = new XmlSerializer(myurl.GetType());
TextWriter writer = new StreamWriter(filename);
sr.Serialize(writer, myurl);
writer.Close();
}
}
}
+++++++++++++++++++++++++++++++++++++++++++++++++++
\\Not sure what this exactly does but I know \\it's separate class as well deals with the XML file reading and writing.
namespace HW_Browser { public class browsinghistory { private string entry1; private string entry2; private string entry3; private string entry4; public string Entry1 { get { return entry1; } set { entry1 = value; } } public string Entry2 { get { return entry2; } set { entry2 = value; } } public string Entry3 { get { return entry3; } set { entry3 = value; } } public string Entry4 { get { return entry4; } set { entry4 = value; } } } } +++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ \\here is where it gets saved to the XML file \\ triggered by a button click try { browsinghistory his = new browsinghistory(); his.Entry1 = toolStripTextBox1.Text; his.Entry2 = toolStripTextBox1.Text; his.Entry3 = toolStripTextBox1.Text; his.Entry4 = toolStripTextBox1.Text; SaveXml.Saveurl(his, "history.xml"); } catch (Exception ex) { MessageBox.Show(ex.Message); } ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ \\ This is where the XML file supposed to displays the value back to the other multi-line text box. if (File.Exists("history.xml")) { XmlSerializer xs = new XmlSerializer(typeof(browsinghistory)); FileStream read = new FileStream("history.xml", FileMode.Open, FileAccess.Read, FileShare.Read); browsinghistory his = (browsinghistory)xs.Deserialize(read); textBox1.Text = his.Entry1; textBox1.Text = his.Entry2; textBox1.Text = his.Entry3; textBox1.Text = his.Entry4; read.Close(); }
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