问题描述
我正在学习为linux编写内核模块作为初学者。我想做的是使用DFS算法将每个任务及其子进程写入内核日志。但是当我使用 Makefile
编译代码时,它显示以上错误:
I'm learning to write kernel modules for linux as a beginner. What I'm trying to do is to write every task and its child process into the kernel log using DFS algorithm. But when I compile the code using Makefile
, it shows the above error:
function declaration isn’t a prototype [-Werror=strict-prototypes]
struct task_struct *current;
它指出了 task_struct
函数DFS。
这是我的代码:
It points out the task_struct
keyword at the function DFS.Here's my code:
# include <linux/init.h>
# include <linux/kernel.h>
# include <linux/module.h>
# include <linux/sched.h>
# include <linux/list.h>
void DFS (struct task_struct *task)
{
struct task_struct *current;
struct list_head *list;
list_for_each (list, &task->children)
{
current = list_entry(list, struct task_struct, sibling);
printk(KERN_INFO "%d\t%d\t%s \n", (int)current->state, current->pid, current->comm);
if (current != NULL)
{
DFS(current);
}
}
}
int DFS_init(void)
{
printk(KERN_INFO "Loading the Second Module...\n");
printk(KERN_INFO "State\tPID\tName\n");
DFS(&init_task);
return 0;
}
void DFS_exit(void)
{
printk(KERN_INFO "Removing the Second Module...\n");
}
任何人都知道如何解决这个问题
Anyone knows how to fix this ??
编辑
我发现错误。看起来像C不允许创建一个变量 * current
。我改成了另一个名字,它编译!!!
I found the error. Seems like C doesn't allows to make a variable called *current
. I changed it to another name and, it compiled !!!
推荐答案
Kernal有一个内置的变量c $ c> current ,它指向当前正在执行进程的用户。如所述,
Kernal has an inbuilt variable (or pointer) called current
which is pointing to users currently executing process. As This book states,
使用 current
作为变量名将给出编译时错误!
So, using current
as a variable name will gives a compile-time error !!!
这篇关于函数声明不是C中的原型的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!