按搜索字词相似度对结果进行排序

问题描述

我有这个用户集合:

{
    "_id" : ObjectId("501faa18a34feb05890004f2"),
    "username" : "joanarocha",
}
{
    "_id" : ObjectId("501faa19a34feb05890005d3"),
    "username" : "cristianarodrigues",
}
{
    "_id" : ObjectId("501faa19a34feb05890006d8"),
    "username" : "anarocha",
}

当我查询以下内容时: db.users.find({'username': /anaro/i}) 结果以自然顺序(插入顺序)排序.

When I query this: db.users.find({'username': /anaro/i}) results are sorted in natural order (insertion order).

我想按相似性搜索词顺序对其进行排序.在这种情况下，结果应按以下顺序返回:

I would like to sort them in a similarity search-term order. In this case results should return by this order:

{
    "_id" : ObjectId("501faa19a34feb05890006d8"),
    "username" : "anarocha",
}
{
    "_id" : ObjectId("501faa18a34feb05890004f2"),
    "username" : "joanarocha",
}
{
    "_id" : ObjectId("501faa19a34feb05890005d3"),
    "username" : "cristianarodrigues",
}

推荐答案

不幸的是，默认情况下，MongoDB不支持全文搜索排名.

Unfortunately, MongoDB doesn't support full text search ranking by default.

首先，您将需要一种算法来计算字符串之间的相似度.请参阅以下链接:

First of all, you will need a algorithm to calculate the similarity between strings. See following links:

字符串相似度算法?

字符串相似度-> Levenshtein距离

然后，您需要使用算法将 javascript函数编写为一个比较两个字符串在查询中传递它.请参阅以下链接以了解如何实现:

Then you need to write a javascript function using the algorithm to compare two strings to pass it in your query. See the following link to see how to achieve that:

Mongo复杂排序?

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