问题描述
寻找在bash的解决方案（将是一个脚本的一部分）。
Looking for a solution in bash (will be part of a script).
由于其形式为someletters_12345_moreleters.ext文件名，我想提取的5位数字，并把它们放入一个变量。
Given a filename in the form "someletters_12345_moreleters.ext", I want to extract the 5 digits and put them into a variable.
所以要强调这一点。我有个字符x个然后是一个下划线两边则另一组的字符的x个包围一个五位序列的文件名。我想坐5位数字并将它放入一个变量。
So to emphasize the point. I have a filename with x number of characters then a five digit sequence surrounded by a single underscore on either side then another set of x number of characters. I want to take the 5 digit number and put that into a variable.
我在，这是可以实现的不同方式的数量非常感兴趣。与大多数事情一样，我相信有很多不同的方法来解决这个问题。
I am very interested in the number of different ways that this can be accomplished. As with most things, I am sure there are a number of different ways to tackle this problem.
推荐答案
使用：
echo 'someletters_12345_moreleters.ext' | cut -d'_' -f 2
更通用的：
INPUT='someletters_12345_moreleters.ext'
SUBSTRING=$(echo $INPUT| cut -d'_' -f 2)
echo $SUBSTRING
这篇关于提取在bash子的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！