问题描述
直到最近我掌握了指针和数组之间的关系和
我终于明白[]是一个运算符。但是我还是不能确定这一点：在一个声明中真正做到了[]：
int array [5];
int matrix [5] [5];
dArray = new int [];
dMatrix = new int * [];
此外，这是否有效（有用？）：
int x;
int * array =& x ;
for（int i = 0; i< some_number; ++ i）
array [i] = //一些东西
Until recently I grasp the relationship between pointers and arrays and
I have finally understand that [ ] is an operator. But I still can''t
quite figure it out: What does really does [ ] in a statement such as:
int array[5];
int matrix[5][5];
dArray = new int[];
dMatrix = new int*[];
Also, is this valid (useful?):
int x;
int *array=&x;
for(int i=0; i<some_number; ++i)
array[i] = //some stuff
推荐答案
不，它对于除'0'以外的''i'的值无效（它有未定义的
行为），因此在正常编程中没用。
V
No, it''s not valid for values of ''i'' other than 0 (it has undefined
behaviour), and therefore not useful in normal programming.
V
我很少迷路！
当我使用类似的东西时：
int array [5];
我说'寻找5块空闲内存来分配int'和
创建一个指针数组到第一个街区是真还是假？
所以，当我说'
int matrix [5] [5];
它看起来是25块而不是5块，但是我不明白[5] [5]
的确意味着什么？
如果这就是它的工作方式那么它意味着什么：
那么
int array [5]
与
相同
int * array = new int [5]
？
I''m a little lost!
When I use something like:
int array[5];
I''m saying "look for 5 block of free memory to allocate int''s and
create a pointer "array" to the first block". True or false?
So when I''m saying
int matrix[5][5];
It looks for 25 blocks instead of 5, but I cn''t understand what [5][5]
really means?
And if that''s the way it works then what it means:
Then
int array[5]
is the same as
int* array = new int[5]
?
我很少迷路！
当我使用类似的东西时：
int array [5];
我说'寻找5块空闲内存来分配int'和
创建一个指针数组到第一个街区是真还是假？
所以，当我说'
int matrix [5] [5];
它看起来是25块而不是5块，但是我不明白[5] [5]
的确意味着什么？
如果这就是它的工作方式那么
int array [5]
与
相同
int * array = new int [5]
？
I''m a little lost!
When I use something like:
int array[5];
I''m saying "look for 5 block of free memory to allocate int''s and
create a pointer "array" to the first block". True or false?
So when I''m saying
int matrix[5][5];
It looks for 25 blocks instead of 5, but I cn''t understand what [5][5]
really means?
And if that''s the way it works then
int array[5]
is the same as
int* array = new int[5]
?
这篇关于运营商[]的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！