本文介绍了std :: string和整数的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 29岁程序员，3月因学历无情被辞！ 显然以下不起作用： int i = 5; std :: string myString =" Number is" + i +请大家祝你好！ 所以有人能告诉我这种方式最好的方法吗？ 我很有信心我没有使用sprintf。 感谢， GA 解决方案 Glen Able < SM ************* @ hotMEmail.com>写道： 显然以下不起作用： int i = 5; std :: string myString =" Number is" + i +谢谢你，; 所以任何人都可以让我知道这种事情最好的方式是什么？我确定它没有使用sprintf。 您可以使用cout样式格式打印到字符串。请参阅常见问题 http://www.parashift.com/c++-faq-lit....html#faq-38.1 2004年7月8日星期四，Glen Able写道： 显然以下不起作用： int i = 5 ; std :: string myString =" Number is" + i +请你好吗？ 所以任何人都可以告诉我这种事情最好的方法是什么？我确定它没有使用sprintf。 谢谢， GA //单程： #include < sstream> #include< string> #include< iostream> 使用命名空间std; int main（） { int i = 5; string myString1 ="数字是 ; string myString2 ="谢谢，请; ostringstream os; os<< myString1<< i<< myString2; string msgString = os.str（）; cout<< msgString<< endl; } 试试 int i = 5; std :: string myString; myString =" Number is" + i +谢谢你， // ANders 2004年7月8日星期四09:28:58 +0100，Glen Able写道： 显然以下不起作用： int i = 5; std :: string myString =" Number is" + i +请你好吗？ 所以任何人都可以告诉我这种事情最好的方法是什么？我确定它没有使用sprintf。 谢谢， GA Obviously the following doesn''t work:int i = 5;std::string myString = "Number is " + i + " thankyou please";So can anyone give me some idea what''s the nicest way to this sort of thing?I''m sure it''s not using sprintf.with thanks,G.A. 解决方案 "Glen Able" <sm*************@hotMEmail.com> writes: Obviously the following doesn''t work:int i = 5;std::string myString = "Number is " + i + " thankyou please";So can anyone give me some idea what''s the nicest way to this sort of thing?I''m sure it''s not using sprintf.You can use cout-style formatting to print to a string. See the FAQ http://www.parashift.com/c++-faq-lit....html#faq-38.1On Thu, 8 Jul 2004, Glen Able wrote: Obviously the following doesn''t work: int i = 5; std::string myString = "Number is " + i + " thankyou please"; So can anyone give me some idea what''s the nicest way to this sort of thing? I''m sure it''s not using sprintf. with thanks, G.A.// one way:#include <sstream>#include <string>#include <iostream>using namespace std;int main(){int i = 5;string myString1 = "The number is ";string myString2 = " thank you, please";ostringstream os;os << myString1 << i << myString2;string msgString = os.str();cout << msgString << endl;}tryint i = 5;std::string myString;myString = "Number is " + i + " thankyou please";// ANdersOn Thu, 08 Jul 2004 09:28:58 +0100, Glen Able wrote: Obviously the following doesn''t work: int i = 5; std::string myString = "Number is " + i + " thankyou please"; So can anyone give me some idea what''s the nicest way to this sort of thing? I''m sure it''s not using sprintf. with thanks, G.A. 这篇关于std :: string和整数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！ 上岸，阿里云！
