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问题描述
是否可以为 xmlrpc-connection 设置客户端端口?
Is it possible to set the clientport for the xmlrpc-connection?
我想说:
客户端应该通过特定的客户端端口创建一个 ServerProxy 对象
或伪代码如下:
serv = xmlrpclib.ServerProxy("server:port","overSpecificClientPort").
推荐答案
尝试定义自定义传输.这应该是这样的:
Try to define a custom transport. This should be something like that:
import xmlrpclib, httplib
class sourcedTransport(xmlrpclib.Transport):
def setSource(self, src):
self.src = src
def make_connection(self, host):
h = httplib.HTTPConnection(host, source_address= self.src)
return h
srcPort = 43040
srcAddress = ('', srcPort)
p = sourcedTransport()
p.setSource(srcAddress)
server = xmlrpclib.ServerProxy("server:port", transport=p)
错误修复 httplib.HTTP => httplib.HTTPConnection
bug fix httplib.HTTP => httplib.HTTPConnection
并在 python 2.7(但不是之前)中检查它是否有效
And checked that it works, in python 2.7 (but not before)
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