本文介绍了" “ yc”不能用作功能“ C ++中的错误的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在使用C ++计算NACA 4位机翼坐标。在这段代码中,我使用了犰狳库的linspace函数将x划分为线性间隔的点。当我使用for循环为每个 x
的值计算 yc
的值时,出现错误 yc不能用作功能。谢谢。
I am calculating NACA 4 digit airfoil coordinates using C++. In this code I used armadillo library's linspace function to divide x into linearly spaced points. When I use a for loop to calculate yc
's value for each x
's value I get error "yc" can not be used as function. Thanks for helping.
#include<iostream>
#include<armadillo>
#include<vector>
using namespace std;
using namespace arma;
int main()
{
float a[3];
float c;
int gp = 100;
cout << "Please Enter NACA 4 digits" << endl;
cout << "Please Enter 1st digit" << endl;
cin >> a[0] ;
cout << "Please Enter 2nd digit" << endl;
cin >> a[1] ;
cout << "Please Enter last 2 digits" << endl;
cin >> a[2] ;
cout << "Please Enter Chord Length" << endl;
cin >> c;
float m=(a[0]*c)/100;
float p=(a[1]*c)/10;
float t=(a[2]*c)/100;
cout << m << endl;
cout << p << endl;
cout << t << endl;
vec x = linspace<vec>(0, c, gp);
float yc;
for(int i=0;i<gp;++i)
{
if (x(i) = 0 && x(i) <= p){
yc(i) = (m/(p*p))*((2*p*(x(i)))-(x(i)*x(i)));
}
if (x(i) > p && x(i) <= c) {
yc(i) =(m/((1-p)*(1-p)))*((1-(2*p))+(2*p*x(i))-(x(i)*x(i)));
}
}
cout<< yc <<endl;
return 0;
}
推荐答案
yc
是单个浮点数。
编译器将 symbol()
视为一个函数呼叫。这就是错误的含义。
The compiler treats symbol( )
as a function call. That is what the error means.
也许创建一个yc数组
float yc[gp];
并使用
yc[i] = ....
如突出显示- yc [gp]
可能不起作用,所以
As highlighted - yc[gp]
may not work, so
float * yc = new float[gp];
在 main()
的末尾
delete []yc;
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