本文介绍了遍历Java中的字符串数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有包含一些组件的 String 数组,这个数组有 5 个组件,它有时会有所不同.我想做的是遍历该数组并获取第一个组件和该组件旁边的组件.因此,第一次我将获得第一个组件和第 2 个组件,第二次将获得数字 2 和 3,第三次获得数字 3 和 4...依此类推,直到您获得最后一个组件.

I have String array with some components, this array has 5 components and it vary some times. What I would like to do is to iterate through that array and get the first component and the component next to that one. So the first time I would get the component number one and the component number 2, the second time would get the number 2 and 3, the third time number 3 and 4... And so on until you get to the last component.

这是我走了多远:

String[] elements = { "a", "a","a","a" };

for( int i = 0; i <= elements.length - 1; i++)
{
    // get element number 0 and 1 and put it in a variable,
    // and the next time get element      1 and 2 and put this in another variable.
}

我怎样才能做到这一点?

How can I accomplish this?

推荐答案

你可以做一个 增强循环(对于java 5及更高版本)用于数组元素的迭代:

You can do an enhanced for loop (for java 5 and higher) for iteration on array's elements:

String[] elements = {"a", "a", "a", "a"};
for (String s: elements) {
    //Do your stuff here
    System.out.println(s);
}

这篇关于遍历Java中的字符串数组的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

07-18 04:23
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