Javascript闭包 - 绑定值而不是引用

问题描述

以下示例摘自本书Javascript：The good parts。作者说，辅助函数返回一个绑定到 var i 的当前值的函数。

The below example was taken from the book, "Javascript: The good parts". The author says that the helper function returns a function that binds to the current value of var i.

任何人都可以解释什么使它绑定VALUE而不是REFERENCE的 var i ，因为帮助函数是 add_the_handler 函数的闭包，应该只能看到 var i 的引用：

Can anyone explain what makes it to bind the VALUE instead of REFERENCE of var i, because helper function is a closure to add_the_handler function and should only see the reference of var i:

var add_the_handlers = function (nodes) {
   var helper = function (i) {
      return function (e) {
        alert(i);
      };
    };
    var i;
    for (i = 0; i < nodes.length; i += 1) {
       nodes[i].onclick = helper(i);
    }
};

推荐答案

如果你说：

nodes[i].onclick = function(){ alert(i) };

函数不会有自己的 i i 未在函数范围内声明。

The function would not have it's own copy of i because i is not declared within the scope of the function.

ve修改上面的代码：

To help you see this better I've modified your above code:

var add_the_handlers = function (nodes) {
    var helper = function(t) {
      // t is in the scope of "helper"
      return function(e){
        // e is in the scope of this anonymous function
        // and is not used
        alert(t);
      };
    };

    // Variables declared here are in the scope of "add_the_handlers"
    var i;
    for (i = 0; i < nodes.length; i += 1) {
       nodes[i].onclick = helper(i);
    }
};

在现实世界中，你经常会看到类似上面的代码缩写为：

In the "real world" you'll often see code like the above shortened to look like this:

var add_the_handlers = function(nodes){
    var i;
    for(i = 0; i < nodes.length; i++)
       nodes[i].onclick = (function(i){ return function(e){ alert(i); }; })(i);
};

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