本文介绍了如何在Python中获得两个变量的逻辑异或?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如何在Python中获得两个变量的逻辑异或?
How do you get the logical xor of two variables in Python?
例如,我有两个我希望是字符串的变量.我想测试其中只有一个包含True值(不是None或空字符串):
For example, I have two variables that I expect to be strings. I want to test that only one of them contains a True value (is not None or the empty string):
str1 = raw_input("Enter string one:")
str2 = raw_input("Enter string two:")
if logical_xor(str1, str2):
print "ok"
else:
print "bad"
^
运算符似乎是按位的,并且未在所有对象上定义:
The ^
operator seems to be bitwise, and not defined on all objects:
>>> 1 ^ 1
0
>>> 2 ^ 1
3
>>> "abc" ^ ""
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: unsupported operand type(s) for ^: 'str' and 'str'
推荐答案
如果您已经将输入归一化为布尔值,则!=为xor.
If you're already normalizing the inputs to booleans, then != is xor.
bool(a) != bool(b)
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