While循环在Bash脚本重新设置数字变量

问题描述

我试图做一个简单的bash脚本做的每个文件的一个东西在一组文件夹。此外，我想算脚本多少文件读取，但是当循环的脚本通，数值变量被复位。

I'm trying to do a simple bash script to do something in one of each file in a set of folders. Also I like to count how many files the script read, but when the script pass of the loop, the numerical variable is reseted.

在code我使用的就是这样

The code I'm using is like that

#!/bin/bash
let AUX=0
find . -type "f" -name "*.mp3" | while read FILE; do
    ### DO SOMETHING with $FILE###
    let AUX=AUX+1
    echo $AUX
done
echo $AUX

我可以看到，辅助线的内循环计数，但最后回声打印0，而变量似乎真的复位。我的控制台输出就是这样

I can see that AUX is counting inside the loop, but the last "echo" prints a 0, and the variable seems to be really reseted. My console output is like that

...
$ 865
$ 866
$ 867
$ 868
$ 0

我想preserve在AUX proccesed文件的数量。任何想法？

I would like to preserve in AUX the number of files proccesed. Any idea?

推荐答案

不要使用管道，它会创建一个子shell。下面的例子。

Do not use the pipe, it creates a subshell. Example below.

#!/bin/bash
declare -i AUX=0
while IFS='' read -r -d '' file; do
    ### DO SOMETHING with $file###
    (( ++AUX ))
    echo $AUX
done < <(find . -type "f" -name "*.mp3")
echo $AUX

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