问题描述
有人能劝什么我做错了。
我想设置qurtz，这样在启动时它会读取XML配置文件。里面的文件也能激活我的HelloEmail_Job.cs类（它是正确创建的，在执行方法IJob的逻辑延伸）的工作。在XML也有，这将触发每分钟（纯粹是为了测试）工作
Can someone advise on what I am doing wrong.I am trying to setup qurtz so that on startup it will read an xml config file. inside the file there is a job that activates my HelloEmail_Job.cs class (it is created correctly, extending IJob with the logic in the execute method). the xml also has a cron trigger for the job that will fire every minute (purely for testing)
但一切都启动时没有错误，但工作永远不会触发。我相信我错配置
but everything starts up without an error, but the job never fires. i am sure I am configuring wrong
我有我的处理调度的生成单，在程序器启动我的应用程序启动（在Global.asax文件）
I have a singleton that handles the generation of my scheduler, the schedular starts on startup of my app (in the global.asax file)
NameValueCollection properties = new NameValueCollection();
properties["quartz.scheduler.instanceName"] = "RemoteServer";
////// set thread pool info
properties["quartz.threadPool.type"] = "Quartz.Simpl.SimpleThreadPool, Quartz";
properties["quartz.threadPool.threadCount"] = "5";
properties["quartz.threadPool.threadPriority"] = "Normal";
properties["quartz.jobStore.type"] = "Quartz.Impl.AdoJobStore.JobStoreTX, Quartz";
properties["quartz.jobStore.useProperties"] = "true";
properties["quartz.jobStore.dataSource"] = "default";
properties["quartz.jobStore.tablePrefix"] = "QRTZ_";
properties["quartz.jobStore.lockHandler.type"] = "Quartz.Impl.AdoJobStore.UpdateLockRowSemaphore, Quartz";
properties["quartz.dataSource.default.connectionString"] = "Data Source=CRAIG-PC\\SQLEXPRESS;Initial Catalog=MCWdb;User ID=sa;Password=mastercrud;";
properties["quartz.dataSource.default.provider"] = "SqlServer-20";
// job initialization plugin handles our xml reading, without it defaults are used
properties["quartz.plugin.xml.type"] = "Quartz.Plugin.Xml.XMLSchedulingDataProcessorPlugin, Quartz";
properties["quartz.plugin.xml.fileNames"] = "~/quartz_jobs.xml";
ISchedulerFactory sf = new StdSchedulerFactory(properties);
_sched = sf.GetScheduler();
我quartz_jobs.xml文件看起来像这样
my quartz_jobs.xml file looks like this
<?xml version="1.0" encoding="UTF-8"?>
<job-scheduling-data xmlns="http://quartznet.sourceforge.net/JobSchedulingData"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
version="2.0">
<processing-directives>
<overwrite-existing-data>true</overwrite-existing-data>
</processing-directives>
<schedule>
<job>
<job-detail>
<name>MyJob</name>
<group>MyJobs</group>
<description>sends out a test email</description>
<job-type>HelloEmail_Job</job-type>
<volatile>false</volatile>
<durable>true</durable>
<recover>false</recover>
<job-data-map>
<entry>
<key>Body</key>
<value>Hello From your website!!!!!!!!</value>
</entry>
</job-data-map>
</job-detail>
<trigger>
<cron>
<name>MyJobTrigger</name>
<group>MyJobs</group>
<description>A description</description>
<job-name>MyJob</job-name>
<job-group>MyJobs</job-group>
<cron-expression>0 0/1 * 1/1 * ? *</cron-expression>
</cron>
</trigger>
</job>
</schedule>
</job-scheduling-data>
我知道程序器与一个简单的触发正确运行的特设工作，因为当我的应用程序创建它们，并调度它们动态地将其完美的作品。但我希望做重复的（通过cron）逻辑和可配置通过XML
I know that the schedular is running correctly for ad hoc jobs with a simple trigger because when my app creates them and schedules them dynamically it works perfectly. but I want the logic made repeatable (through a cron), and configurable through a xml
我的直觉是，JOB_TYPE值是错误的。
my gut feeling is that the JOB_TYPE value is wrong.
感谢
推荐答案
您的工作类型需要被指定为
Your job type needs to be specified as
<job-type>Fully.Qualified.Type.Name, AssemblyNameWithoutTheDllExtension</job-type>
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