本文介绍了如何列出在bash脚本中声明的变量?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
在我的bash脚本,还有很多变数,我必须做出什么来拯救他们到文件。
我的问题是如何列出我的脚本声明的所有变量和获取列表是这样的:
VARIABLE1 = ABC
变量2 =高清
VARIABLE3 = GHI
解决方案
设置
将输出变量,遗憾的是它也将输出功能定义也是如此。
幸运的是POSIX模式只能输出变量:
(设置-o POSIX;集)|减
管道到少
,或重定向到您想要的选项。
因此,要在短短的剧本获得声明的变量:
(设置-o POSIX;集)GT; /tmp/variables.before
源脚本
(设定-o POSIX;集)GT; /tmp/variables.after
差异/tmp/variables.before /tmp/variables.after
RM /tmp/variables.before /tmp/variables.after
(或至少基于:-)东西)
In my script in bash, there are lot of variables, and I have to make something to save them to file.My question is how to list all variables declared in my script and get list like this:
VARIABLE1=abc
VARIABLE2=def
VARIABLE3=ghi
解决方案
set
will output the variables, unfortunately it will also output the functions defines as well.
Luckily POSIX mode only outputs the variables:
( set -o posix ; set ) | less
Piping to less
, or redirect to where you want the options.
So to get the variables declared in just the script:
( set -o posix ; set ) >/tmp/variables.before
source script
( set -o posix ; set ) >/tmp/variables.after
diff /tmp/variables.before /tmp/variables.after
rm /tmp/variables.before /tmp/variables.after
(Or at least something based on that :-) )
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