本文介绍了不兼容的类型错误的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 29岁程序员，3月因学历无情被辞！#include<windows.h>#include<stdio.h>#include <ctype.h>typedef struct ret{long long memory;char* drive;};int main(){struct ret total_memory;total_memory=size_show(GetLogicalDrives());return 0;}struct ret size_show(long int n ){struct ret to_func;long long ii;long int i, k, andmask;char a[5]="E://";char c;printf("%d",strlen(a));printf("drives available\n");for ( i = 32 ; i >= 0 ; i-- ){andmask = 1 << i;k = n & andmask;if(k!=0){k=i+65;printf("%c:\n",k);}}printf("drive you want to clear\n");scanf("%c",&c);a[0]=toupper(c);printf("%s.\n",a);printf("%d\n",strlen(a));i=strcmp("E://",a);printf("%d",i);k=GetDiskFreeSpaceEx(a,NULL,NULL,&ii);printf("%ld",k);printf("%ld",ii);to_func.memory=ii;strcpy(to_func.drive,a);return to_func;} 我无法弄清楚上面的代码有什么问题，我希望从中返回两个值函数因此我使用结构，我期待代码中的警告而不是错误。 感谢您提前的帮助 我尝试了什么： 我尝试更改数据类型I can't figure out the problem the above code has, I want two values to be returned from the function hence I am using a struct, I was expecting warnings in the code instead getting errors.Thanks for your help in advanceWhat I have tried:I tried changing types of the data推荐答案一个函数不能返回一个结构，最多它可以返回一个指向结构的指针。 第二个问题，那个结构不能像你那样在堆栈上创建。 以下是一些讲座： C编程语言 - 维基百科，免费的百科全书 [ ^ ] HT tps：//hassanolity.files.wordpress.com/2013/11/the_c_programming_language_2.pdf [ ^ ] http://www.ime.usp.br/~pf/Kernighan-Ritchie/C-Programming-Ebook.pdf [ ^ ]A function can't return a structure, at best it can return a pointer to the structure.Second problem, that structure can't be created on stack like you have done.Here is some lecture:The C Programming Language - Wikipedia, the free encyclopedia[^]https://hassanolity.files.wordpress.com/2013/11/the_c_programming_language_2.pdf[^]http://www.ime.usp.br/~pf/Kernighan-Ritchie/C-Programming-Ebook.pdf[^] struct ret to_func;// ... strcpy(to_func.drive,a); 您在函数 size_show 的顶部声明了您的结构，但您从未初始化它。因此，当您尝试将某些内容复制到 to_func.drive 时，它会失败，因为您有一个未初始化的指针。 另外你的驱动器规格是错误的，你使用双正斜杠而不是反斜杠，应该E：\\。 如果您告诉我们哪行代码会出错，这会有所帮助。You declare your struct at the top of the function size_show, but you never initialise it. So when you try to copy something to to_func.drive it fails because you have an uninitialised pointer.Also your drive specifications are wrong, you are using double forward slashes instead of backslashes, should be "E:\\".And it would help if you told us which line of code gives the error. 这篇关于不兼容的类型错误的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！ 上岸，阿里云！
