静态函数已声明但未在C ++中定义

问题描述

在使用C ++的以下代码中出现错误.

I'm getting an error from the following code using C++.

Main.cpp

#include "file.h"

int main()
{
   int k = GetInteger();
   return 0;
}

File.h

static int GetInteger();

File.cpp

#include "file.h"

static int GetInteger()
{
   return 1;
}

我得到的错误:

Error C2129: static function 'int GetInteger(void)' declared but not defined.

我已经阅读了著名的文章，但不了解此代码有什么问题.

I've read the famous article "Organizing Code File in C and C++", but don't understand what is wrong with this code.

推荐答案

在C ++中，全局/命名空间范围内的 static 表示该功能/变量仅在定义该功能/变量的翻译单元中使用，不在其他翻译单位中.

In C++, static at global/namespace scope means the function/variable is only used in the translation unit where it is defined, not in other translation units.

在这里，您尝试使用的静态函数与定义其定义单元( File.cpp )不同的转换单元( Main.cpp ).

Here you are trying to use a static function from a different translation unit (Main.cpp) than the one in which it is defined (File.cpp).

删除 static ，它应该可以正常工作.

Remove the static and it should work fine.

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