问题描述
使用最新版本的Spring Boot通过Restful Web Service读取示例JSON ...
Am using the latest version of Spring Boot to read in a sample JSON via Restful Web Service...
这是我的pom.xml:
Here's my pom.xml:
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0
http://maven.apache.org/maven-v4_0_0.xsd"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<modelVersion>4.0.0</modelVersion>
<groupId>org.springframework</groupId>
<artifactId>myservice</artifactId>
<version>0.1.0</version>
<parent>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-parent</artifactId>
<version>1.2.2.RELEASE</version>
</parent>
<properties>
<java.version>1.7</java.version>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
<project.reporting.outputEncoding>UTF-8</project.reporting.outputEncoding>
</properties>
<dependencies>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-web</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-test</artifactId>
<scope>test</scope>
</dependency>
<dependency>
<groupId>org.springframework.data</groupId>
<artifactId>spring-data-rest-webmvc</artifactId>
</dependency>
<dependency>
</dependencies>
<build>
<plugins>
<plugin>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-maven-plugin</artifactId>
</plugin>
</plugins>
</build>
<repositories>
<repository>
<id>spring-releases</id>
<name>Spring Releases</name>
<url>https://repo.spring.io/libs-release</url>
</repository>
<repository>
<id>org.jboss.repository.releases</id>
<name>JBoss Maven Release Repository</name>
<url>https://repository.jboss.org/nexus/content/repositories/releases</url>
</repository>
</repositories>
<pluginRepositories>
<pluginRepository>
<id>spring-releases</id>
<name>Spring Releases</name>
<url>https://repo.spring.io/libs-release</url>
</pluginRepository>
</pluginRepositories>
</project>
这是我的网络服务代码:
Here's my web service code:
import org.springframework.web.bind.annotation.RequestBody;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.RestController;
@RestController
@RequestMapping("/myservice")
public class BaseService {
@RequestMapping(value="/process", method = RequestMethod.POST)
public void process(@RequestBody String payload) throws Exception {
System.out.println(payload);
}
}
当我使用以下命令调用它时:
When I invoke it using the following command:
curl -H "Accept: application/json" -H "Content-type: application/json"
-X POST -d '{"name":"value"}' http://localhost:8080/myservice/process
我收到以下错误消息:
{"timestamp":1427515733546,"status":400,
"error":"Bad Request",
"exception":
"org.springframework.http.converter.HttpMessageNotReadableException","
message":
"Could not read JSON: Can not deserialize instance of java.lang.String
out of START_OBJECT token\n at
[Source: java.io.PushbackInputStream@8252f; line: 1, column: 1];
nested exception is com.fasterxml.jackson.databind.JsonMappingException:
Can not deserialize instance of java.lang.String out of START_OBJECT token\n
at [Source: java.io.PushbackInputStream@8252f; line: 1, column: 1]",
"path":"/myservice/process"
我唯一想做的事情do传递一些有效的JSON(通过curl作为字符串),并查看String有效负载是否以{name:value}
The only thing I am trying to do is pass in some valid JSON (as a string via curl) and to see if the String payload enters the process method as {"name":"value"}
进入流程方法我可能做错了什么?
What am I possibly doing wrong?
感谢您花时间阅读此内容...
Thank you for taking the time to read this...
推荐答案
我认为使用JSON最简单/最方便的方法是使用类似于JSON的Java类:
I think the simplest/handy way to consuming JSON is using a Java class that resembles your JSON: https://stackoverflow.com/a/6019761
但是如果你不能使用Java类,你可以使用这两种解决方案中的一种。
But if you can't use a Java class you can use one of these two solutions.
解决方案1:您可以从控制器接收 Map< String,Object>
:
Solution 1: you can do it receiving a Map<String, Object>
from your controller:
@RequestMapping(
value = "/process",
method = RequestMethod.POST)
public void process(@RequestBody Map<String, Object> payload)
throws Exception {
System.out.println(payload);
}
使用您的请求:
curl -H "Accept: application/json" -H "Content-type: application/json" \
-X POST -d '{"name":"value"}' http://localhost:8080/myservice/process
解决方案2:否则您可以将POST有效负载作为字符串
获取:
Solution 2: otherwise you can get the POST payload as a String
:
@RequestMapping(
value = "/process",
method = RequestMethod.POST,
consumes = "text/plain")
public void process(@RequestBody String payload) throws Exception {
System.out.println(payload);
}
然后根据需要解析字符串。请注意,必须在控制器上指定 consumes =text / plain
。
在这种情况下,您必须使用更改您的请求内容类型:text / plain
:
Then parse the string as you want. Note that must be specified consumes = "text/plain"
on your controller.In this case you must change your request with Content-type: text/plain
:
curl -H "Accept: application/json" -H "Content-type: text/plain" -X POST \
-d '{"name":"value"}' http://localhost:8080/myservice/process
这篇关于尝试使用Spring Boot REST从POST读取JSON字符串的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!